我试图在其中创建一个包含多个数组的数组。 我使用CloudKit获取数据。
import UIKit
import CloudKit
var questionsCount = 0
var questionsArray = [String]()
class hvadvilduhelstViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
//firstfield.setTitle("Klik her for at starte!", forState: .Normal)
//secondfield.setTitle("Klik her for at starte!", forState: .Normal)
firstfield.titleLabel?.lineBreakMode = NSLineBreakMode.ByWordWrapping
firstfield.titleLabel?.textAlignment = NSTextAlignment.Center
secondfield.titleLabel?.lineBreakMode = NSLineBreakMode.ByWordWrapping
secondfield.titleLabel?.textAlignment = NSTextAlignment.Center
let container = CKContainer.defaultContainer()
let publicData = container.publicCloudDatabase
let query = CKQuery(recordType: "Questions", predicate: NSPredicate(format: "TRUEPREDICATE", argumentArray: nil))
publicData.performQuery(query, inZoneWithID: nil) { results, error in
if error == nil { // There is no error
for entry in results! {
let firstOne = [entry["Question1"] as! String]
let secondOne = firstOne + [entry["Question2"] as! String]
let thirdOne = secondOne + [String(entry["Question1Rating"] as! Int)]
let fourthOne = thirdOne + [String(entry["Question2Rating"] as! Int)]
let fithOne = fourthOne + [String(entry["Reports"] as! Int)]
questionsArray = questionsArray + fithOne
print(questionsArray)
}
}
else {
print(error)
}
}
}
使用以前的代码我在控制台输出中得到这个:
["Dette er en test1", "Dette er en test2", "0", "0", "0", "test2", "test2", "0", "0", "0"]
而不是这(我想要的输出):
[["Dette er en test1", "Dette er en test2", "0", "0", "0"], ["test2", "test2", "0", "0", "0"]]
我很简单,无法弄清楚如何做到这一点。我的计划是获取大量记录并将它们放入这个庞大的阵列中(以便于使用'值')是否有更简单/更好的方法来执行此操作?
抱歉我的英语,而不是我的母语。 谢谢你的帮助!
答案 0 :(得分:1)
当你遇到这样的问题时,做一个游乐场并进行实验并做一些思考。这就是你在做什么,实质上是:
var arr = [String]()
for _ in (1...3) {
let first = ["Mannie"]
let second = first + ["Moe"]
let third = second + ["Jack"]
arr = arr + third
}
arr // ["Mannie", "Moe", "Jack", "Mannie", "Moe", "Jack", "Mannie", "Moe", "Jack"]
这不是你想要的,所以不要这样做。首先,正如你的问题标题所说,你需要一个数组数组。那么,你不想最终得到[String]
;你刚刚告诉我们你想要一个[[String]]
(一串字符串数组)!所以首先要做出改变:
var arr = [[String]]()
现在,当您构建数组并将其插入数组数组时,请使用append
方法(而不是+
运算符):
arr.append(third)
结果如下:
var arr = [[String]]()
for _ in (1...3) {
let first = ["Mannie"]
let second = first + ["Moe"]
let third = second + ["Jack"]
arr.append(third)
}
arr // [["Mannie", "Moe", "Jack"], ["Mannie", "Moe", "Jack"], ["Mannie", "Moe", "Jack"]]
现在就去做你真实的代码吧。
答案 1 :(得分:0)
请改为尝试:
import UIKit
import CloudKit
var questionsCount = 0
var questionsArray = [[String]]()
class hvadvilduhelstViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
//firstfield.setTitle("Klik her for at starte!", forState: .Normal)
//secondfield.setTitle("Klik her for at starte!", forState: .Normal)
firstfield.titleLabel?.lineBreakMode = NSLineBreakMode.ByWordWrapping
firstfield.titleLabel?.textAlignment = NSTextAlignment.Center
secondfield.titleLabel?.lineBreakMode = NSLineBreakMode.ByWordWrapping
secondfield.titleLabel?.textAlignment = NSTextAlignment.Center
let container = CKContainer.defaultContainer()
let publicData = container.publicCloudDatabase
let query = CKQuery(recordType: "Questions", predicate: NSPredicate(format: "TRUEPREDICATE", argumentArray: nil))
publicData.performQuery(query, inZoneWithID: nil) { results, error in
if error == nil { // There is no error
for entry in results! {
let firstOne = entry["Question1"] as! String
let secondOne = entry["Question2"] as! String
let thirdOne = String(entry["Question1Rating"] as! Int)
let fourthOne = String(entry["Question2Rating"] as! Int)
let fifthOne = String(entry["Reports"] as! Int)
questionsArray.append([firstOne, secondOne, thirdOne, fourthOne, fifthOne])
print(questionsArray)
}
}
else {
print(error)
}
}
}
}
值得注意的是,questionsArray
现在属于[[String]]
类型,而不仅仅是[String]
,而对于每个entry
,您想要追加新的[String]