如果omp for以omp并行嵌套，那么openmp会做什么

Question

#include <omp.h>
#include <stdio.h>

int main()
{
    int n = 4;
    int i, j;
    #pragma omp parallel num_threads(2) private(i)
    for (i = 0;i < n;i++)
    {
        int outer_tid = omp_get_thread_num();
        printf("outside thread id is %d, i = %d.\n", outer_tid,i);

        if (i%2 == 0)
        #pragma omp for
        for (j = 0;j < n;j += 2)
        {
            printf("even, outside thread is %d, inner thread id is %d, i = %d, j = %d.\n", outer_tid , omp_get_thread_num(), i, j);
        }

        else
        #pragma omp for
        for (j = 1;j < n;j += 2)
        {
            printf("odd, outside thread is %d, inner thread id is %d, i = %d, j = %d.\n", outer_tid , omp_get_thread_num(), i, j);
        }
    }
    return 0;
}

输出

outside thread id is 0, i = 0.
even, outside thread is 0, inner thread id is 0, i = 0, j = 0.
outside thread id is 1, i = 0.
even, outside thread is 1, inner thread id is 1, i = 0, j = 2.
outside thread id is 0, i = 1.
odd, outside thread is 0, inner thread id is 0, i = 1, j = 1.
outside thread id is 1, i = 1.
odd, outside thread is 1, inner thread id is 1, i = 1, j = 3.
outside thread id is 0, i = 2.
even, outside thread is 0, inner thread id is 0, i = 2, j = 0.
outside thread id is 1, i = 2.
even, outside thread is 1, inner thread id is 1, i = 2, j = 2.
outside thread id is 0, i = 3.
odd, outside thread is 0, inner thread id is 0, i = 3, j = 1.
outside thread id is 1, i = 3.
odd, outside thread is 1, inner thread id is 1, i = 3, j = 3.

显然，

for (i = 0;i < n;i++)
    {
        int outer_tid = omp_get_thread_num();
        printf("outside thread id is %d, i = %d.\n", outer_tid,i);

已由线程0和1执行。但是嵌套的omp for directive没有重复执行。我想为线程0，当i = 0时，它会与嵌套for和线程1并行，当i = 0时，所以有重复。但输出证明我错了。 openmp处理这种情况的策略是什么？