我有这个查询,它在会员资格表中找到与(memberid)具有相同电子邮件的所有用户,并带回任何其他具有匹配电子邮件的用户
select tenant,first,last,memberid,email,ipaddress,password
from membership
where email IN (
SELECT email
FROM membership where memberid = <Parameters.Member ID>
GROUP BY email)
我还需要能够恢复与当前行的用户具有相同密码或ipaddress的所有用户的计数。我尝试过使用case语句但无法获得正确的结果。
答案 0 :(得分:2)
在许多平台(包括sql server)中,您可以使用窗口函数。窗口函数允许您计算与当前行具有相同密码或ipaddress的用户的计数。如果这是你想要的
select tenant,first,last,memberid,email,ipaddress,password,
count(memberid) OVER (partition by ipaddress) as ipaddress_count,
count(memberid) OVER (partition by password) as password_count
from membership
where email IN (
SELECT email
FROM membership where memberid = <Parameters.Member ID>
GROUP BY email)
答案 1 :(得分:0)
select match.email, match.tenant, match.first, match.last
, match.memberid, match.ipaddress, match.password
, count(match.memberid) OVER (partition by match.ipaddress) as ipCount
, count(match.memberid) OVER (partition by match.password) as passwordCount
, member.memberid as [member.memberid], member.ipaddress as [member.ipaddress], member.password as [member.password]
from membership as match
join membership as member
on member.email = match.email
and member.memberid = <Parameters.Member ID>
答案 2 :(得分:-1)
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical">
<FrameLayout
android:layout_width="match_parent"
android:layout_height="50dp">
<Button
android:layout_width="match_parent"
android:layout_height="50dp"
android:text="some text"
android:paddingRight="28dp"
/>
<View
android:layout_width="20dp"
android:layout_height="20dp"
android:background="@drawable/bg.png"
android:layout_gravity="right|center_vertical"
android:marginRight="8dp"
/>
</FrameLayout>
</LinearLayout>