Question

我试图创建一个Android应用程序，这将是一个简单的数学游戏。它有多个难度级别，包括简单，中等，难度，非常难。简易级别涉及2个整数（6 + 6）之间的算术问题，3之间的中等（2 + 2-1），4（2 + 2-1 / 3）之间的硬和5（2 + 3 * 5）之间的非常硬-3 + 2）。我必须生成随机整数和随机算术运算。我能够显示每个难度级别的问题和操作，但我找不到正确的答案。无论我输入什么答案，程序都会显示错误。例如，如果我回答3 + 3-1为5或任何其他，它将始终显示错误。对于2个整数我使用了switch语句，并且它工作正常，但涉及多个算术运算的问题总是错误的任何想法如何做到这一点。我将代码放在下面

    private final int ADD_OPERATOR = 0, SUBTRACT_OPERATOR = 1, MULTIPLY_OPERATOR = 2, DIVIDE_OPERATOR = 3;
    private String[] operators = {"+", "-", "x", "/"};
    operator = random.nextInt(operators.length);

    switch(operator)
    {
    case ADD_OPERATOR:
    answer = operand1+operand2;
    break;
    case SUBTRACT_OPERATOR:
    answer = operand1-operand2;
    break;
    case MULTIPLY_OPERATOR:
    answer = operand1*operand2;
    break;
    case DIVIDE_OPERATOR:
    answer = operand1/operand2;
    break;
    default:
    break;
    }
    question.setText(operand1+" "+operators[operator]+" "+operand2);
    //Operand 1 and Operand 2 are 2 Random Integers

     public void onClick(View view)
   {
    //button clicked
    if(view.getId()==R.id.enter){
        //enter button
        String answerContent = answerTxt.getText().toString();
        if(!answerContent.endsWith("?"))
        {
            //we have an answer}
            int enteredAnswer =   Integer.parseInt(answerContent.substring(2));
            int exScore = getScore();

        if(enteredAnswer==answer){
            //correct
            scoreTxt.setText("Score: "+(exScore+1));
            response.setImageResource(R.drawable.tick);
            response.setVisibility(View.VISIBLE);
        }else{
            //incorrect
            scoreTxt.setText("Score: 0");
            response.setImageResource(R.drawable.cross);
            response.setVisibility(View.VISIBLE);
        }

        chooseQuestion();
    }}
    else if(view.getId()==R.id.clear){
        //clear button
        answerTxt.setText("= ?");
    }
    else {
        //number button
        response.setVisibility(View.INVISIBLE);
        int enteredNum = Integer.parseInt(view.getTag().toString());
        if(answerTxt.getText().toString().endsWith("?"))
            answerTxt.setText("= "+enteredNum);
        else
            answerTxt.append(""+enteredNum);
    }
}

我将用户答案存储为答案文字。有关如何为多个算术运算执行此操作的任何帮助。感谢

算术运算符生成器

0 个答案: