Question

我想把文本字段中的数据插入到数据库中，但我的代码不起作用（虽然控制台中没有错误），我做错了什么？这是一个代码：

        Query query = entityManager.createNativeQuery("INSERT INTO Employee(idemployee, name, lastname,"
                + "gender, position, salary, phonenumber, adress) VALUES (:idemployee, :name, :lastname, :gender,"
                + ":position, :salary, :phonenumber, :adress )");

        Employee em = new Employee();

        em.setEID(emplID.getText());
        em.setName(emplName.getText());
        em.setLastName(empllastName.getText());
        em.setGender(emplGender.getText());
        em.setPosition(emplPosition.getText());
        em.setSalary(emplSalary.getText());
        em.setPhonenumber(emplphoneNumber.getText());
        em.setAddress(emplAdress.getText());

        query.setParameter("idemployee", em.getEID());
        query.setParameter("name", em.getEID());
        query.setParameter("lastname", em.getEID());
        query.setParameter("gender", em.getEID());
        query.setParameter("position", em.getEID());
        query.setParameter("salary", em.getEID());
        query.setParameter("phonenumber", em.getEID());
        query.setParameter("adress", em.getEID());

        entityManager.getTransaction().commit();

Answer 1

未为本机查询定义命名参数的使用。从JPA规范（第3.6.3节命名参数）：

命名参数遵循第4.4.1节中定义的标识符规则。命名参数的使用适用于Java Persistence查询语言，并未针对本机查询定义。只有位置参数绑定可以便携地用于本机查询。

请尝试以下方法：

Query query = entityManager.createNativeQuery("INSERT INTO Employee(idemployee, name, lastname,"
            + "gender, position, salary, phonenumber, adress) VALUES (?1, ?2, ?3, ?4,"
            + "?5, ?6, ?7, ?8 )");

    Employee em = new Employee();

    em.setEID(emplID.getText());
    em.setName(emplName.getText());
    em.setLastName(empllastName.getText());
    em.setGender(emplGender.getText());
    em.setPosition(emplPosition.getText());
    em.setSalary(emplSalary.getText());
    em.setPhonenumber(emplphoneNumber.getText());
    em.setAddress(emplAdress.getText());

    query.setParameter(1, em.getEID());
    query.setParameter(2, em.getEID());
    query.setParameter(3, em.getEID());
    query.setParameter(4, em.getEID());
    query.setParameter(5, em.getEID());
    query.setParameter(6, em.getEID());
    query.setParameter(7, em.getEID());
    query.setParameter(8, em.getEID());

    query.setString("status", "purged");
    int rowsCopied=query.executeUpdate();

    entityManager.getTransaction().commit();

请注意，在JPA＆gt; = 2.0中，您可以在本机查询中使用命名参数。

有关详细信息，请按照 JPA/Hibernate Native Queries do not recognize Parameters

Hibernate - INSERT QUERY不起作用

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