Question

我正在尝试根据图形度值制作直方图。但是当我运行我的代码时，我收到了这个错误：

x只有一个数据点。必须给出垃圾箱或范围kwarg。

如果有人能告诉我我做错了什么，我会很感激。

代码是：

import numpy as np
import pandas
import networkx as nx
import unicodecsv as csv
import operator
import matplotlib.pyplot as plt
import scipy.stats as st
import community
import plotly.plotly as py

#graph
path="hero-network.csv"

graph = nx.Graph(name="Heroic Social Network")
with open(path, 'rb') as data:
    reader = csv.reader(data)
    for row in reader:
        graph.add_edge(*row)

#histogram
plt.hist(graph.degree().values() , bins=500)
plt.title("Connectedness of Marvel Characters")
plt.xlabel("Degree")
plt.ylabel("Frequency")
plt.show()

csv datafile看起来像这样（前10个节点）：

LITTLE, ABNER,"PRINCESS ZANDA"
LITTLE, ABNER,"BLACK PANTHER/T'CHAL"
BLACK PANTHER/T'CHAL,"PRINCESS ZANDA"
LITTLE, ABNER,"PRINCESS ZANDA"
LITTLE, ABNER,"BLACK PANTHER/T'CHAL"
BLACK PANTHER/T'CHAL,"PRINCESS ZANDA"
STEELE, SIMON/WOLFGA,"FORTUNE, DOMINIC"
STEELE, SIMON/WOLFGA,"ERWIN, CLYTEMNESTRA"
STEELE, SIMON/WOLFGA,"IRON MAN/TONY STARK "
STEELE, SIMON/WOLFGA,"IRON MAN IV/JAMES R."

Answer 1

Matplotlib将iterables解释为单个值。在python 3中，dict.values返回一个可迭代的。将其转换为列表，它将起作用：

plt.hist(list(graph.degree().values()), bins=500)

在Python3中制作简单的图形直方图

1 个答案: