我有以下JSON格式，我想从中提取密钥。
我想获得以下密钥
covg_AccdntDeath_Slf，
covg_DILong_Slf，
covg_LITwentyYr_Slf，
covg_LITenYr_Slf，
covg_GrpOffOvr_Slf，
covg_LIAnnual_Slf，
txtCampaignCode，
associationAccronym < /强>
这是我的JSON数据：
{
"covg_AccdntDeath_Slf":{
"txtGNumber":"G-29003-0",
"txtPlanName":"Accidental Death and Dismemberment Insurance",
"hidProdCode":"999",
"rdTypeOfCovg":"New",
"slidBenefitAmt":"50000",
"productCategory":"AD"
},
"covg_DILong_Slf":{
"txtGNumber":"G-29002-0",
"txtPlanName":"Long Term Disability",
"hidProdCode":"601-a",
"rdTypeOfCovg":"New",
"txtMaxBenefitAmt":"$15,000",
"selWaitingPeriod":"30 Days",
"slidMonBenefitAmt":"1000",
"productCategory":"DI"
},
"covg_LITwentyYr_Slf":{
"txtGNumber":"G-29005-0",
"txtPlanName":"20-Year Level Term Life Insurance",
"hidProdCode":"121",
"rdTypeOfCovg":"New",
"slidBenefitAmt":"100000",
"productCategory":"LI"
},
"covg_LITenYr_Slf":{
"txtGNumber":"G-29004-0",
"txtPlanName":"10-Year Level Term Life Insurance",
"hidProdCode":"102",
"rdTypeOfCovg":"New",
"slidBenefitAmt":"100000",
"productCategory":"LI"
},
"covg_GrpOffOvr_Slf":{
"txtGNumber":"G-29002-1",
"txtPlanName":"Office Overhead Expense Disability Insurance",
"hidProdCode":"603",
"rdTypeOfCovg":"New",
"slidBenefitAmt":"1000",
"txtMaxBenefitAmt":"$20,000",
"selWaitingPeriod":"30 Days",
"selBenefitDuration":"24 months",
"productCategory":"OO"
},
"covg_LIAnnual_Slf":{
"txtGNumber":"G-29000-0",
"txtPlanName":"Traditional Term Life Insurance",
"hidProdCode":"99999",
"rdTypeOfCovg":"New",
"slidBenefitAmt":"100000",
"productCategory":"LI"
},
"txtCampaignCode":"",
"associationAccronym":"ACS"
}
我尝试过以下代码。
<html>
<head>
<script>
var input = above JSON String.
var keys = [];
console.log('Length : '+input.length);
for(var i = 0;i<input.length;i++)
{
Object.keys(input[i]).forEach(function(key){
if(keys.indexOf(key) == -1)
{
keys.push(key);
}
});
}
console.log('KKKK: '+keys);
</script>
</head>
</html>
答案 0 :(得分：0)
您不需要所有代码。
1）将JSON解析为对象：var obj = JSON.parse(json);。
2）对象没有长度，因此使循环冗余。 Object.keys(obj)确实有一个长度。
3）您正在迭代对象键并将它们放在一个新数组中。 Object.keys(obj)无论如何返回一个数组，因为在对象中键不能重复，检查当前键是否在keys中的条件也是多余的。
您需要的只是Object.keys(obj)，然后您可以使用forEach来迭代数组。
类似的东西：
var keys = Object.keys(obj);
keys.forEach(function (el) { console.log(el); });
甚至只是：
Object.keys(obj).forEach(function (el) { console.log(el); });