Question

给定字符串和模式，用字符串中的单个X替换所有连续出现的模式。要获得清晰的视图，请参阅下面的示例。

输入：

The first line of input contains an integer T denoting the number of test cases.
The first line of each test case is string str.
The second line of each test case contains a string s,which is a pattern.

输出：

Print the modified string str.

约束：

1 ≤ T ≤ 100
1 ≤ size of str,s ≤ 1000

示例：

输入

2
abababcdefababcdab
ab
geeksforgeeks
geeks

输出

XcdefXcdX
XforX

代码： -

n = int(raw_input())
for i in range(n):
  x=raw_input()
  y=raw_input()
  x1=x.replace(y,"X")
  x2=""
  count=0
  for i in x1:
    if i=='X':
      if count==0:
        x2+=i
        count+=1
      else:
        count+=1
        ## do nothing         
    elif i!='X':
      count=0
      x2+=i
print (x2)

Answer 1

我对这个问题的回答，首先我用X替换所有子串的出现，然后用一个X替换所有后续的X：

n = int(input())
for i in range(n):
    x = input()
    y = input()
    x1 = x.replace(y,"X")
    flag = False
    new_x1 = ""
    for i in x1:
        if i == "X" and flag == False:
            flag = True
            new_x1 += i
        elif i != "X" :
            flag = False
            new_x1 += i
    print (new_x1)

输出：

2
abababcdefababcdab
ab
#XcdefXcdX
geeksforgeeks
geeks
#XforX

Answer 2

regexp

的简单回答

import re
n = int(input())
for i in range(n):
    x = input()
    y = input()
    x1 = x.replace(y,"X")

    final = re.sub(r'(.)\1{1,}', r'\1', x1)
    print (final)

正则表达式将替换多次出现的任何字符(x)

python中字符串替换函数出错

2 个答案: