Question

我用，

$up = request::file('image')->move('../public/images');

将图片上传到“公共/图片”目录。

我尝试通过使用“dd（）”来了解“$ up”的数据。

我得到数据，

 UploadedFile {#183 ▼
 -test: false
 -originalName: "Brackpoints.png"
 -mimeType: "image/png"
 -size: 148276
 -error: 0
  path: "/tmp"
  filename: "phpmU8PvU"
  basename: "phpmU8PvU"
  pathname: "/tmp/phpmU8PvU"
  extension: ""
  realPath: "/tmp/phpmU8PvU"
  aTime: 2016-02-15 13:57:39
  mTime: 2016-02-15 13:57:39
  cTime: 2016-02-15 13:57:39
  inode: 1443211
  size: 148276
  perms: 0100600
  owner: 900
  group: 900
  type: "file"
  writable: true
  readable: true
  executable: false
  file: true
  dir: false
  link: false
}

如果我尝试“print_r（）”，那么我明白了，

 Illuminate\Http\UploadedFile Object
 (
  [test:Symfony\Component\HttpFoundation\File\UploadedFile:private] => 
[originalName:Symfony\Component\HttpFoundation\File\UploadedFile:private] => Brackpoints.png
[mimeType:Symfony\Component\HttpFoundation\File\UploadedFile:private] => image/png
[size:Symfony\Component\HttpFoundation\File\UploadedFile:private] => 148276
[error:Symfony\Component\HttpFoundation\File\UploadedFile:private] => 0
[pathName:SplFileInfo:private] => /tmp/phpMhUyh0
[fileName:SplFileInfo:private] => phpMhUyh0
 )

   Symfony\Component\HttpFoundation\File\File Object
  (
      [pathName:SplFileInfo:private] => ../public/images/phpMhUyh0
      [fileName:SplFileInfo:private] => phpMhUyh0
  )

在这里，我想获得图片的名称和类型......

我怎么能得到？

Answer 1

$up->getClientOriginalName();

$up->getMimeType();

Answer 2

试试这个

echo $up->originalName;

Laravel 5 |图片上传|无法获取上传变量的数据

2 个答案: