Question

def sum_of_squares_of_digits(a):
    a = input("Enter the rpm ")
    s = sum(int(c) ** 2 for c in str(a))
    print s
    m = s * 323
    print m
    r = a%10
    e = a/10
    x = e%10
    u = int(str(r) + str(e))
    f = u%10
    h = u/10
    l = h%10
    t = int(str(l) + str(f))
    result = m+t
    print u
    print t
    print result

sum_of_squares_of_digits(2)

在上面的代码中，我需要取＆＃34; result＆＃34;的值。并将其作为＆＃34; a＆＃34;的输入。并执行10次。

Answer 1

您应首先return来自您的函数的变量result：

def sum_of_squares_of_digits(a):
    ...
    return result

然后你可以调用该函数并使用for loop执行10次：

res = sum_of_squares_of_digits(2) # first call with 2 like in your program
for i in range(10):
    res = sum_of_squares_of_digits(res) # next 10 calls with the returned value

如何使函数在python中执行n次

1 个答案: