我想写sas代码(proc-sql)。问题是如何创建变量VP_Trans(在下表中)。下表是指某段时间内的客户交易。 我想计算一下客户基于他最近5笔交易的VP交易数量。包括第五项交易 例如客户1根据1.2.-11.2之间的交易计算了5个VP交易。
+---------+-------------+-----------+----------+
| cust id | Trans Dates | TransType | Vp_Trans |
+---------+-------------+-----------+----------+
| 1 | 2015-02-01 | VP | NA |
| 1 | 2015-02-03 | Vp | NA |
| 1 | 2015-02-06 | VP | NA |
| 1 | 2015-02-06 | Vp | NA |
| 1 | 2015-02-11 | Vp | 5 |
| 1 | 2015-02-13 | MG | 4 |
| 1 | 2015-02-17 | Vp | 4 |
| 1 | 2015-02-18 | mg | 3 |
| 1 | 2015-02-19 | mg | 2 |
| 1 | 2015-02-20 | mg | 1 |
| 1 | 2015-02-21 | vp | 2 |
| 2 | 2015-02-01 | VP | NA |
| 2 | 2015-02-03 | mg | NA |
| 2 | 2015-02-06 | mg | NA |
| 2 | 2015-02-06 | Vp | NA |
| 2 | 2015-02-11 | Vp | 3 |
| 2 | 2015-02-13 | MG | 2 |
| 2 | 2015-02-17 | Vp | 3 |
| 2 | 2015-02-18 | mg | 3 |
| 2 | 2015-02-19 | mg | 2 |
| 2 | 2015-02-20 | mg | 1 |
| 2 | 2015-02-21 | mg | 1 |
| 2 | 2015-02-22 | mg | 0 |
+---------+-------------+-----------+----------+
答案 0 :(得分:0)
如果您的DBMS支持Windowed Aggregates,那么它只是一个简单的移动计数:
select
cust_id, Trans_Dates, TransType,
count(case when TransType = 'VP' then 1 end)
over (partition bycust_id
order by Trans_Dates
rows 4 preceding) as Vp_Trans
from tab
答案 1 :(得分:0)
使用5元素数组来跟踪type =' VP'的检查。使用MOD()
函数实现环绕索引。以下是您的示例数据:
data have ;
input id Date Type $ Expected ;
informat date yymmdd10.;
format date yymmdd10.;
cards;
1 2015-02-01 VP .
1 2015-02-03 Vp .
1 2015-02-06 VP .
1 2015-02-06 Vp .
1 2015-02-11 Vp 5
1 2015-02-13 MG 4
1 2015-02-17 Vp 4
1 2015-02-18 mg 3
1 2015-02-19 mg 2
1 2015-02-20 mg 1
1 2015-02-21 vp 2
2 2015-02-01 VP .
2 2015-02-03 mg .
2 2015-02-06 mg .
2 2015-02-06 Vp .
2 2015-02-11 Vp 3
2 2015-02-13 MG 2
2 2015-02-17 Vp 3
2 2015-02-18 mg 3
2 2015-02-19 mg 2
2 2015-02-20 mg 1
2 2015-02-21 mg 1
2 2015-02-22 mg 0
;;;;
以下是计算VP_TRANS的数据步骤。
data want ;
do n=1 by 1 until (last.id);
set have ;
by id date ;
array flags (5) ;
flags(mod(n,5)+1)= upcase(type)='VP';
if n>= 5 then VP_trans=sum(of flags(*));
output;
end;
drop flags: ;
run;
proc print; run;