Question

如何将12:02:21.3213之类的字符串值解析为NSTimeInterval？从iOS8开始提供的NSDateComponentsFormatter仅支持格式化，而不支持解析。

Answer 1

Bartosz Hernas提供的解决方案为我工作，谢谢！

为方便起见，这里是 Swift 3 ：

func parseDuration(_ timeString:String) -> TimeInterval {
    guard !timeString.isEmpty else {
        return 0
    }

    var interval:Double = 0

    let parts = timeString.components(separatedBy: ":")
    for (index, part) in parts.reversed().enumerated() {
        interval += (Double(part) ?? 0) * pow(Double(60), Double(index))
    }

    return interval
}

Answer 2

以下是如何在Swift中执行此操作：

func parseDuration(timeString:String) -> NSTimeInterval {
    guard !timeString.isEmpty else {
        return 0
    }

    var interval:Double = 0

    let parts = timeString.componentsSeparatedByString(":")
    for (index, part) in parts.reverse().enumerate() {
        interval += (Double(part) ?? 0) * pow(Double(60), Double(index))
    }

    return interval
}

它适用于像 2:12:12， 02:01:23.123213

Answer 3

这是我用@Bartosz答案制作的Swift 5版本

def ShowAnotherWin(i=0):
    if i < len(YourImageList):
        win = Toplevel()
        image = ImageTk.PhotoImage(file='C:/Users/capture.PNG')
        win.geometry(YourImageList[i])
        canvas =Canvas(win, width=420, height=560)
        canvas.create_image(0, 0, image= image, anchor=NW)
        canvas.pack()
        canvas.image = image # need to keep a reference to image
        win.overrideredirect(1)
        #win.mainloop()  # no need to call mainloop() here
        root.after(4000, ShowAnotherWin, i+1)

...

ShowAnotherWin()

如何将字符串解析为NSTimeInterval

3 个答案: