Question

我试图存储拍摄的照片但是......

文件已创建，但JPEG为空。
我想使用JPEG文件进行编码并将其发送到服务器，因为位图是我想要的低位定义。

那么如何解决这两个问题？

public void takePicture() {
    Toast.makeText(MainActivity.this,"Entra no takePicture",Toast.LENGTH_LONG).show();
    Log.d("entra", "Take Picture");
    Intent takePictureIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
    // Ensure that there's a camera activity to handle the intent
    if (takePictureIntent.resolveActivity(getPackageManager()) != null) {
        // Create the File where the photo should go
        photoFile = null;
        try {
            Log.d("entra","Vai criar file");
            photoFile = createImageFile();
        } catch (IOException ex) {
            // Error occurred while creating the File
            Log.d("Erro",ex.getMessage());
        }
        // Continue only if the File was successfully created
        if (photoFile != null) {

            startActivityForResult(takePictureIntent, REQUEST_TAKE_PHOTO);
        }
    }
}



@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    Toast.makeText(MainActivity.this,"Entra no onActivityResult()",Toast.LENGTH_LONG).show();
    if (requestCode ==  REQUEST_TAKE_PHOTO && resultCode == RESULT_OK) {
        Bundle extras = data.getExtras();
        image_BMP = (Bitmap) extras.get("data");
        bitmap.setImageBitmap(image_BMP);
        Log.d("Onactivity result()"," Passa aqui");
        myphoto= ImageUtility.getBytes(Bitmap.createBitmap(image_BMP));

    }
    Toast.makeText(MainActivity.this,"sai do onActivityResult()",Toast.LENGTH_LONG).show();
}

public static File createImageFile() throws IOException {
    // Create an image file name

    Log.d("entra", "Create File");
    String timeStamp = new   SimpleDateFormat("yyyyMMdd_HHmmss").format(new Date());
    String imageFileName = "JPEG_" + timeStamp + "_";
    File storageDir = Environment.getExternalStoragePublicDirectory(
            Environment.DIRECTORY_PICTURES);
    File pic = File.createTempFile(
            imageFileName,  /* prefix */
            ".jpg",         /* suffix */
            storageDir      /* directory */
    );

    // Save a file: path for use with ACTION_VIEW intents
    mCurrentPhotoPath = "file:" + pic.getAbsolutePath();
    Log.d("entra", "Create File");

    return pic;
}

Answer 1

这是我使用的，它的工作原理：

        Uri image = data.getData();
        String[] filePathColumn = { MediaStore.Images.Media.DATA };
        Cursor cursor = getContentResolver().query(image,
                filePathColumn, null, null, null);
        cursor.moveToFirst();

        int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
        String filePath = cursor.getString(columnIndex);
        cursor.close();

        BitmapFactory.Options options = new BitmapFactory.Options();
        options.inPreferredConfig = Bitmap.Config.ARGB_8888;
        Bitmap bitmap = BitmapFactory.decodeFile(filePath, options);
        imageView.setBitmap(bitmap);

在onActivityResult中使用而不是：

     Bundle extras = data.getExtras();
    image_BMP = (Bitmap) extras.get("data");
    bitmap.setImageBitmap(image_BMP);
    Log.d("Onactivity result()"," Passa aqui");
    myphoto= ImageUtility.getBytes(Bitmap.createBitmap(image_BMP));

您不必自己创建文件。相机会照顾它。您可以删除这些内容的代码。

编辑：

要传递自定义图像位置，您可以在调用startActivityForResult（）

之前使用它

 Uri fileUri = Uri.fromFile(yourFile);
 intent.putExtra(MediaStore.EXTRA_OUTPUT, fileUri);

Answer 2

intentCamera.putExtra(MediaStore.EXTRA_OUTPUT,Uri.fromFile(photoFile));

在startActivityforresult之前添加此行并存储您的路径，因为有时活动会重新启动并且您将获得一个空指针，

    @Override
    protected void onSaveInstanceState(Bundle outState) {
        super.onSaveInstanceState(outState);           
        outState.putString("imagePath", mCurrentPhotoPath);
    }


    @Override
    protected void onRestoreInstanceState(Bundle savedInstanceState) {
        super.onRestoreInstanceState(savedInstanceState);
        // get the file path
        mCurrentPhotoPath = savedInstanceState.getString("imagePath");
    }

然后你可以从路径中获取文件，你可以上传文件或者你可以使用

从文件中读取位图

Bitmap bitmap = BitmapFactory.decodeFile(new File(filePath))

按照您的意愿随后使用位图

在目录中存储文件的问题？

2 个答案: