Question

我需要使用symfony2创建一个REST api。没有UI，没有形式只是一个REST API。

我尝试创建一个简单的CRUD系统但是我对更新有疑问。

那么，

config.yml

fos_rest:
    param_fetcher_listener: force
    routing_loader:
        default_format: json                            # All responses should be JSON formated
        include_format: false
    exception:
        enabled: true

FeatureController：

<?php

namespace AppBundle\Controller;

use AppBundle\Entity\Feature;

use FOS\RestBundle\Controller\Annotations;
use FOS\RestBundle\Controller\FOSRestController;
use FOS\RestBundle\Request\ParamFetcher;
use Guzzle\Http\Message\Request;
use Nelmio\ApiDocBundle\Annotation\ApiDoc;
use FOS\RestBundle\Controller\Annotations\RouteResource;
use FOS\RestBundle\Controller\Annotations\RequestParam;
use FOS\RestBundle\Controller\Annotations\QueryParam;
use FOS\RestBundle\View\View;

/**
 * @RouteResource("Feature", pluralize=false)
 */
class FeatureController extends FOSRestController
{
    /**
     * @param ParamFetcher $params
     * @RequestParam(name="type", requirements="[0-9]", default="0", description="type")
     * @RequestParam(name="name", requirements="[a-z]+", description="name")
     *
     * @return array
     */
    public function postAction(ParamFetcher $params){
        $feature = new Feature();
        $feature
            ->setType($params->get('type'))
            ->setName($params->get('name'));

        $em = $this->getDoctrine()->getManager();
        $em->persist($feature);
        $em->flush();

        $view = View::create();
        $view->setStatusCode(201);
        return $this->handleView($view);
    }

    /**
     * @param $id
     * @param ParamFetcher $paramFetcher
     * @RequestParam(name="type", requirements="[0-9]", default="0", description="type")
     * @RequestParam(name="name", requirements="[a-z]+", description="name")
     *
     * @return \Symfony\Component\HttpFoundation\Response
     */
    public function patchAction($id, ParamFetcher $paramFetcher){

        $view = View::create();
        $view
            ->setStatusCode(200)
            ->setData([$id, 'params' => $paramFetcher->all()]);
        return $this->handleView($view);
    }

    /**
     * @param $id
     * @param ParamFetcher $paramFetcher
     * @QueryParam(name="page", requirements="\d+", description="Page of the overview.")
     * 
     * @return Response
     */
    public function getAction($id, ParamFetcher $paramFetcher){

        $view = View::create();
        $view->setData(['id' => $id, 'params' => $paramFetcher->all()])->setStatusCode(200);
        return $this->handleView($view);
    }
}

当我使用此url / feature / 5？page = 55的getAction时，响应是正确的

{
  "id": "5",
  "params": {
    "page": "55"
  }
}

$ id，ParamFetcher $ paramFetcher工作正常。

当我使用postAction with / feature和body

时

{
  "type" : 2,
  "name" : "aze"
}

它也可以。

但是当我尝试将patchAction与/ feature / 5和body一起使用时 { ＆＃34;类型＆＃34; ：5，＆＃34;名称＆＃34; ：＆＃34; newName＆＃34; }

回复是：

{
  "code": 400,
  "message": "Parameter type value '' violated a constraint (This value should not be null.)"
}

有你的想法吗？

PS：这是我第一次使用FOSRestBundle，如果你有一些最佳实践，请不要犹豫。

使用FOSRestBundle和symfony2修补/放置错误

0 个答案: