当我加载表格然后激活搜索时，我可以在tableview中获取搜索数据。为了使我的应用程序更快，我创建了一个仅用于搜索的单独视图。但我无法通过搜索数据填充我的tableview。我可以看到我使用print（数据）正确获取数据，但是我的表没有填充。
class YazarTableViewController: UITableViewController, UISearchResultsUpdating, UISearchBarDelegate {
var searchResults: [JSON]? = []
var searchController = UISearchController()
@IBOutlet weak var searchButton: UIBarButtonItem!
@IBAction func searchButtonTouched(sender: AnyObject) {
showSearchBar()
}
func showSearchBar() {
self.searchController = ({
let controller = UISearchController(searchResultsController: nil)
controller.searchResultsUpdater = self
controller.searchBar.delegate = self
controller.dimsBackgroundDuringPresentation = true
controller.searchBar.alpha = 0
navigationItem.setLeftBarButtonItem(nil, animated: true)
UIView.animateWithDuration(0.5, animations: {
controller.searchBar.alpha = 1
}, completion: { finished in
controller.searchBar.becomeFirstResponder()
})
self.tableView.tableHeaderView = controller.searchBar
return controller
})()
}
}
func updateSearchResultsForSearchController(searchController: UISearchController)
{
self.searchResults?.removeAll(keepCapacity: false)
if (!searchController.searchBar.text!.isEmpty){
let parameters = ["q" : searchController.searchBar.text]
var searchURL = "http://apilink.com/" + String(parameters) + "/1"
searchURL = searchURL.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())!
Alamofire.request(.GET, searchURL, encoding: .JSON)
.responseJSON{ response in
guard response.result.error == nil else {
// got an error in getting the data, need to handle it
print("error calling GET on /posts/1")
print(response.result.error!)
return
}
if let value: AnyObject = response.result.value {
let post = JSON(value)
if let data = post[].arrayValue as [JSON]?{
self.searchResults = data
self.tableView.reloadData()
print(data)
}
}
}
}
}