Question

我正在使用CakePHP 3.x开展项目。

我有UserAddress，ServiceRequests，Service型号。

service/view/$id上有一个按钮，点击后会要求用户从service-requests/serviceArea中选择一个地址列表，其中包含用户添加的地址列表。 service-requests/serviceArea视图将包含select按钮，点按此按钮会在add控制器中调用ServiceRequests操作并传递两个参数serviceId和userAddressId

这是我创建的serviceArea函数。

public function serviceArea($id = null)
    {
        public $uses = array('UserAddress');
        $service = $id;
        $query = $userAddresses->find('all')
          ->where(['UserAddresses.user_id =' => $this->Auth->user('id')]);



        $this->set(compact('userAddresses'));
        $this->set('_serialize', ['userAddresses']);
    }

如何显示地址并将$service参数传递到serviceArea视图。

我是CakePHP的新手，所以如果您认为问题不完整，我们将不会对其进行任何编辑，而不是进行投票。

谢谢。

编辑2

感谢您的回答@jazzcat

根据您的代码更改我的代码并访问http://domain.com/service-requests/service-area/$id。它显示错误为 Record not found in table "service_requests"

并指向ServiceRequestsController行 33

包含第33行的ServiceRequestController是

<?php
namespace App\Controller;

use App\Controller\AppController;

/**
 * ServiceRequests Controller
 *
 * @property \App\Model\Table\ServiceRequestsTable $ServiceRequests
 */
class ServiceRequestsController extends AppController
{

    /**
    * isAuthorized method
    *
    */
    public function isAuthorized($user)
    {
      $action = $this->request->params['action'];

      // The add and index actions are always allowed.
      if(in_array($action, ['index', 'add', 'serviceRequests'])) {
        return true;
      }
      // All other actions require an id.
      if (empty($this->request->params['pass'][0])) {
        return false;
      }

      // Check that the service request belongs to the current user.
      $id = $this->request->params['pass'][0];
      $serviceRequest = $this->ServiceRequests->get($id);  // line : 33
      if($serviceRequest->user_id == $user['id']) {
        return true;
      }
      return parent::isAuthorized($user);
    }

        /* Other actions */
}
?>

Answer 1

这对我有用。

刚刚在serviceArea方法

中添加了isAuthorized操作名称

if(in_array($action, ['index', 'add', 'serviceArea'])) {
        return true;
}

它按预期正常工作。

Answer 2

您的代码有很多错误。请阅读docs

表名为user_addresses还是user_address？你好像混在一起。

假设您的表名为 user_addresses

，以下是正确的方法

public function serviceArea($id = null)
{
        $this->loadModel('UserAddresses');

        $userAddresses = $this->UserAddresses->find('all')
            ->where(['UserAddresses.user_id =' => $this->Auth->user('id')]);

        // If you want to filter on the serviceArea ID aswell
        if($id)
            $userAddresses->andWhere(['id' => $id]);

        // Setting SerivceArea ID to compact makes it available in view.
        $serviceAreaId = $id;

        $this->set(compact('userAddresses', 'serviceAreaId'));
        $this->set('_serialize', ['userAddresses']);
}

此片段：

$id = $this->request->params['pass'][0];
$serviceRequest = $this->ServiceRequests->get($id);  // line : 33

只检查传递给方法的第一个参数是否存在于ServiceRequests中。

（那个参数可以是任何东西，你必须在创建该控制器中的所有方法时记住这一点，也就是说至少......坏）

我假设表示service_requests表与users表相关联，而service_requests表中存在user_id列。

如果是这种情况，这应该有效：

public function isAuthorized($user)
{
      $action = $this->request->params['action'];

      // The add and index actions are always allowed.
      if(in_array($action, ['index', 'add'])) {
        return true;
      }

      // Is not authorized if an argument is not passed to the method.
      // Don't know why you'd want this , but sure.
      if (empty($this->request->params['pass'][0])) {
        return false;
      }

      // Check that the service request belongs to the current user.
      $user_id = $this->Auth->user('id');
      $serviceRequest = $this->ServiceRequests->find()->where(['ServiceRequests.user_id' => $user_id])->first();
      if(!empty($serviceRequest)) {
        return true;
      }
      return parent::isAuthorized($user);
}

CakePHP 3：显示来自其他模型的数据，并通过动作传递url中的参数

2 个答案: