h = soup.findAll("div", {"id": "products"})
for row in h:
b = row.findAll("div", {"class": "gd-row"})
for a in b:
c = a.findAll("div", {"class": "gd-col"})
for d in c:
e = d.findAll("div", {"class": "product-unit"})
for f in e:
g = f.findAll("div", {"class": "pu-details"})
for h in g:
i = h.findAll("div", {"class": "pu-title"})
for k in i:
l = k.findAll('a')
for z in l:
text = z.get('href')
title = str(z.get_text().strip())
urldict.update({counter: text})
print (str(counter) + ')' + title)
titlelist.append(title)
counter = counter + 1
print ("\nSeems we found more than one same mobile type, help us by selecting appropiate model \n")
user_choice = input("\nEnter your choice (number) which matches exactly:")
url_from_search = "http://www.xyzabc.com{}".format(
urldict.get(user_choice).split('&')[0])
任何人都可以帮我吗?我试图在beautifulsoup的帮助下进行html解析。上面给出的代码是抛出属性错误。可能是什么问题?如果可能,请帮助我。
答案 0 :(得分:3)
显然,user_choice
密钥不在urldict
字典中,urldict.get(user_choice)
返回None
。假设您使用的是Python 3并且urldict
键是整数,则需要在进行查找之前将输入数转换为整数:
user_choice = int(input("\nEnter your choice (number) which matches exactly:"))
url_from_search = "http://www.acxcs.com{}".format(
urldict.get(user_choice).split('&')[0])
另外,你应该处理"缺失键"情况更好。例如:
user_choice = int(input("\nEnter your choice (number) which matches exactly:"))
if user_choice not in urldict:
print("Error, the number is not valid")
else:
url_from_search = "http://www.acxcs.com{}".format(urldict[user_choice].split('&')[0])