Question

我是Java课程的新手，我正在努力学习一门课程。该计划应该模拟乌龟和野兔之间的比赛。每个都有基于随机生成的数字的各种动作（在赛车板上移动的方式）。我在生成随机数时遇到问题。以下是我的错误消息。任何人都可以帮我修复错误信息问题吗？此外，如果您在我的代码中看到任何需要修复或其他任何内容的其他内容，我们将非常感谢您的帮助。谢谢，这里是带有以下错误消息的代码。附：我使用蓝色J来编写和编译我的代码：

import java.util.Random;

class Race
{
    int [] race = new int[70];
    int tortoise;
    int hare;
    Random randomGenerator = new Random();
    public boolean again = true;
    public void StartRace()
    {
        tortoise = 1;
        hare = 1;
        System.out.println("AND THEY'RE OFF!!!!");
        while (tortoise < 70 && hare < 70)
        {
            MoveHare();
            MoveTortoise();
            DisplayCurrentLocation();
            String request;
        } //end while
        if 
            (tortoise > hare)
        {
            System.out.println("\n TORTOISE WINS!!");
        }
        else if
            (hare > tortoise)
        {   
            System.out.println("\n HARE WINS!!!");
        }
        else if
            (hare == tortoise)
        {
            System.out.println("TIE!!!");
        }
    }

    public void MoveTortoise()
    {
        int n = randomGenerator.next(1, 10);
        //fast plod
        if ( n <= 5)
            tortoise += 3;
        //slip
        else if (n == 9 || n == 10)
            tortoise -= 6;
        //slow plod
        else if (n == 6 || n == 7 || n == 8)
            ++tortoise;
            // protect from going past start
        if (tortoise < 1)
            tortoise = 1;
       // to make sure game ends
        else if (tortoise > 70)
            tortoise = 70;
    }// end tortoise
    public void MoveHare()
    {
        // randomize move
        int percent = randomGenerator.Next(1, 10);
        // determine moves by graph
        //big hop
        if (percent == 1 || percent == 2)
            hare += 9;
        //big slip
        else if (percent == 6)
            hare -= 12;
        // small hop
        else if (percent == 3 || percent == 5)
            ++hare;
        // )small slip
        else if (percent == 7 || percent == 8)
            hare -= 2;
        else if (percent == 9 || percent == 10)
            hare += 0;
        //ensure hare doesn't go past start
        if (hare < 1)
            hare = 1;
        // ensure hare doesnt go past end
        else if (hare > 70)
            hare = 70;
    } // end movehare
    public void DisplayCurrentLocation()
    {
        //this is the location of each on the array
        for (int count = 1; count <= 70; count++)
            // same spot
            if (count ==tortoise && count ==hare)
            { 
                System.out.println("OUCH");
            }
            else if (count == hare)
            { 
                System.out.println("H");
            }
            else if (count == tortoise)
            {
                System.out.println("T");
            }
           else
               System.out.println();

    }
public class RaceTest
{
    public static void main ( String[] args)
    {
        Race Application = new Race();
        string request;
        do
     {
        Application.StartRace();
        System.out.println ("");
        System.out.println("Do you want to Play again y/n");
        request = Console.ReadKey();
        if (request == "Y" || request == "y")
        {
            again = true;
        }
        else
        {
            again = false;
        }
     }
    while (again == true);
        System.out.println("Thank you for Playing");
   }
 }
}

错误消息：类java.util.random中的下一个方法不能应用于给定的类型; required：int，found：int，int;原因：实际和正式的参数列表长度不同

感谢所有帮助。

Answer 1

有几个问题。

首先，方法next(int)受到保护，这意味着它不打算由客户端（Random类的用户）调用。所以你应该使用方法nextInt()。

其次，要生成任意范围内的随机整数，方法nextInt(int bound)是最接近它的，它返回0到bound-1之间的整数（包括¹），所以要使用相同的效果

int n = randomGenerator.nextInt(10) + 1;

这将生成0到9之间的随机数，然后加1以使范围为1..10。

¹正式地，它返回[0..bound)范围内的整数

随机Ints：不能应用于给定类型

1 个答案: