我的模型中有一些数据(在一个名为results
的变量中),我想根据它们的键将它组织成数组。 I.E,每个genreName值都应该被推入genres []数组,每个actorID都进入cast []数组。
results
:
#<Genre genreName: "Fantasy">
#<Genre genreName: "Comedy">
#<Genre genreName: "Children">
#<Genre genreName: "Animation">
#<Genre genreName: "Adventure">
#<Actor actorID: "tom_hanks", actorName: "Tom Hanks">
#<Actor actorID: "tim_allen", actorName: "Tim Allen">
#<Actor actorID: "don_rickles", actorName: "Don Rickles">
#<Actor actorID: "jim_varney", actorName: "Jim Varney">
#<Actor actorID: "wallace_shawn", actorName: "Wallace Shawn">
#<Director directorID: "john_lasseter", directorName: "John Lasseter">
#<Country countryName: "USA">
#<Location locationName: "N/A">
你会建议什么?我试图在Ruby中完成这个。
修改
将所有对象值添加到Hash中可能会更有意义,但我担心唯一的键名...
答案 0 :(得分:0)
String TIME_PATTERN = "^\\d\\d:\\d\\d\\s[AP]M$";
final JTextField tf = new JTextField("00:00 AM", 8);
((AbstractDocument)tf.getDocument()).setDocumentFilter(new DocumentFilter() {
public void replace(FilterBypass fb, int offs, int length, String str, AttributeSet a) throws BadLocationException {
String text = fb.getDocument().getText(0, fb.getDocument().getLength());
text = text.substring(0, offs) + str + text.substring(offs + length);
if(text.matches(TIME_PATTERN)) {
super.replace(fb, offs, length, str, a);
return;
}
text = fb.getDocument().getText(0, fb.getDocument().getLength());
if(offs == 2 || offs == 5)
tf.setCaretPosition(++offs);
if(length == 0 && (offs == 0 ||offs == 1 ||offs == 3 ||offs == 4 ||offs == 6))
length = 1;
text = text.substring(0, offs) + str + text.substring(offs + length);
if(!text.matches(TIME_PATTERN))
return;
super.replace(fb, offs, length, str, a);
}
public void insertString(FilterBypass fb, int offs, String str, AttributeSet a) throws BadLocationException { }
public void remove(FilterBypass fb, int offset, int length) throws BadLocationException { }
});
这将迭代结果中的每个对象,并返回一个包含每个genreName字段的数组,只包含类&#34;类型&#34;的对象。然后,您可以执行与其他字段类似的操作。
答案 1 :(得分:0)
(编辑:我可能误解了这个问题。我把数据作为字符串数组,但似乎更有可能是类实例。)
genre_names = results.map { |object| object.genreName if object.class.name == "Genre" }
你可以这样做:
results = <<_.lines
#<Genre genreName: "Fantasy">
#<Genre genreName: "Comedy">
#<Genre genreName: "Children">
#<Genre genreName: "Animation">
#<Genre genreName: "Adventure">
#<Actor actorID: "tom_hanks", actorName: "Tom Hanks">
#<Actor actorID: "tim_allen", actorName: "Tim Allen">
#<Actor actorID: "don_rickles", actorName: "Don Rickles">
#<Actor actorID: "jim_varney", actorName: "Jim Varney">
#<Actor actorID: "wallace_shawn", actorName: "Wallace Shawn">
#<Director directorID: "john_lasseter", directorName: "John Lasseter">
#<Country countryName: "USA">
#<Location locationName: "N/A">
_
然后
R = /
\b # Match a word break
(genreName|actorID|cast) # Match one of three strings in capture group 1
\b # Match a word break
(?= # Begin a positive lookahead
:\s+\" # Match : >= 1 whitespace double quote
(\w+) # Match >= 1 word characters in capture group 2
\" # Match double quote
) # End postive lookahead
/x # Extended/free-spacing regex definition mode
h = results.each_with_object({ genreName: [], actorID: [], cast: [] }) { |s,h|
s.scan(R) { h[$1.to_sym] << $2 } }
#=> {:genreName=>["Fantasy", "Comedy", "Children", "Animation", "Adventure"],
# :actorID=>["tom_hanks", "tim_allen", "don_rickles", "jim_varney", "wallace_shawn"],
# :cast=>[]}
等等。