Question

我遇到了一个问题：我创建了一个简单的用户跟踪系统，因此用户可以互相关注。我正在使用名为follows的表来存储关系。我在我的hasMany类中创建了一个User关系，并且在检索结果时我得到了我期望的结果，但是，我想从users表中获取一些额外的信息，例如用户名，头像等。我该怎么做？

follows表

// following_id is the person being followed

public function up()
{
    Schema::create('follows', function (Blueprint $table) {
        $table->increments('id');
        $table->integer('user_id')->unsigned();
        $table->integer('following_id')->unsigned();
        $table->timestamps();

        $table->unique(['user_id', 'following_id']);
        $table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');
    });
}

User班

class User extends Authenticatable
{
    // a user can have many followers
    public function followers()
    {
        return $this->hasMany(Follow::class, 'following_id');
    }


    // a user may be following many people
    public function following()
    {
        return $this->hasMany(Follow::class);
    }
}

我在UsersController中调用的方法来查看结果

// route is /{username}/followers

public function followers($username)
{
    $user = User::where('username', $username)->first();

    // get the user's followers
    $followers = $user->following;

    return $followers;
}

目前的结果是

[
    {
        id: 24,
        user_id: 3,
        following_id: 1,
        created_at: "2016-02-13 11:42:59",
        updated_at: "2016-02-13 11:43:02"
    }
]

但是，我希望它们如下：其中fredflintstone是ID为1的用户;例如。;跟随用户3的用户

[
    {
        id: 24,
        user_id: 3,
        following_id: 1,
        following_username: 'fredflintstone',
        created_at: "2016-02-13 11:42:59",
        updated_at: "2016-02-13 11:43:02"
    }
]

我还创建了一个Follow模型，该模型目前是空的。我尝试在其中添加反belongsTo关系，但它不起作用。也许我做错了？

Answer 1

我一直在使用laravel很长一段时间，如果laravel内置了'with'的模型，我建议你使用join

以下是使用连接的代码，根据您的使用进行修改

    public function followers($username)
        {
            $user = User::where('username', $username)->first();
//Follower your model name for the follows table
//if you dont have a model use DB::table('follows') instead
            $followers=Follower::where('user_id',$user->id)
              ->join('users as follower','follower.id','=','follows.following_id')
              ->select('follows.id','follows.following_id','follows. user_id','follower.name as following_username')->get();


            return $followers;
        }

Answer 2

想出来。我需要将users表加入查询。

public function following()
{
    return $this->hasMany(Follow::class, 'user_id')
        ->join('users', 'users.id', '=', 'follows.following_id')
        ->select('user_id','username');
}

Laravel 5.2用户/关注系统：hasMany Relation

2 个答案: