是否可以在JAX-WS中生成xmlns属性而不是前缀?
示例:来自包myns.a的对象A包含来自包myns.b的一些对象B1,B2。生成的SOAP消息:
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:a="urn:myns/a" xmlns:b="urn:myns/b">
<soapenv:Header/>
<soapenv:Body>
<a:A1>
<b:B1>123456</b:B1>
<b:B2>abc</b:B2>
</a:A1>
</soapenv:Body>
</soapenv:Envelope>
但是,我需要以这种方式生成它(因此应删除前缀b并且包myns.b中的所有对象都应具有xmlns属性):
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:a="urn:myns/a">
<soapenv:Header/>
<soapenv:Body>
<a:A1>
<B1 xmlns="urn:myns/b">123456</B1>
<B2 xmlns="urn:myns/b">abc</B2>
</a:A1>
</soapenv:Body>
</soapenv:Envelope>
有一种简单的方法,如何处理?例如,在package-info.java级别?
答案 0 :(得分:1)
我使用自定义SOAPHandler解决了这个问题,并从urn:myns / b命名空间中的元素中删除了前缀。
简化代码段:
@Override
public boolean handleMessage(SOAPMessageContext context) {
SOAPBody body = context.getMessage().getSOAPPart().getEnvelope().getBody();
//do recursivelly, this is just example
Iterator iter = body.getChildElements();
while (iter.hasNext()) {
Object object = iter.next();
if (object instanceof SOAPElement) {
SOAPElement element = (SOAPElement) object;
if("urn:myns/b".equals(element.getNamespaceURI())){
element.setPrefix("");
}
}
}