Question

我需要打印自然的nos。 1,2，... n使父进程打印所有奇数，子进程打印所有偶数，所有这些都需要使用POSIX信号完成。我将如何完成这项工作？

输出应为：

家长：1 孩子：2
家长：3
...

Answer 1

对你提供你目前所拥有的东西并解释什么不能按预期工作可能更有益，但这是我想出的：

#include <stdio.h>
#include <sys/types.h>
#include <unistd.h>
#include <signal.h>
#include <stdlib.h>

#define READY_SIGNAL SIGUSR1

/* The ready flag is set when READY_SIGNAL is received.
 * It is needed so that when we wake up from sigsuspend
 * we know whether or not the signal received was READY_SIGNAL. */
volatile sig_atomic_t ready;
void make_ready(int i) { ready = 1; }

int
main (int argc, char *argv[])
{
  pid_t cpid, ppid;  /* pids of the child and parent */
  /* Signal masks for sigprocmask and sigsuspend */
  sigset_t block_mask, wait_mask;
  unsigned long c = 1;   /* The counter */
  unsigned long n = 100; /* The default max count value */
  struct sigaction act;

  /* Override the default max count if provided */
  if (argv[1])
    n = strtoul(argv[1], NULL, 10);

  /* Prepare signal masks */
  sigemptyset(&wait_mask);
  sigemptyset(&block_mask);
  sigaddset(&block_mask, READY_SIGNAL);

  /* Set the signal mask for the parent to ignore READY_SIGNAL until
   * we are ready to receive it, the mask will be inherited by the child,
   * needed to avoid race conditions */
  sigprocmask(SIG_BLOCK, &block_mask, NULL);

  /* Register the signal handler, will be inherited by the child */
  act.sa_flags = 0;
  act.sa_handler = make_ready;
  sigemptyset(&act.sa_mask);
  sigaction(READY_SIGNAL, &act, NULL);

  /* Get the parent's process id, needed for the child to send signals
   * to the parent process, could alternatively use getppid in the child */
  ppid = getpid();

  /* Call fork, storing the child's process id needed for the parent to
   * send signals to the child */
  cpid = fork();

  if (cpid < 0) {
    perror("Fork failed");
    exit(EXIT_FAILURE);
  }

  if (cpid == 0) {
    /* Child */
    c = 2;  /* Child's first number will always be 2 */
    if (c > n) exit(0); /* If c > n we have nothing to do */

    do {
      /* Suspend until we receive READY_SIGNAL */
      while (!ready) sigsuspend(&wait_mask);

      /* Print out number, flush for proper output sequencing when output
         is not a terminal. */
      printf("Child: %lu\n", c);
      fflush(stdout);

      ready = 0; /* Reset ready flag */
      c += 2; /* Increment counter */

      /* Wake up parent process */
      kill(ppid, READY_SIGNAL);
    } while (c <= n);  
  } else {
    /* Parent */
    for (;;) {
      /* Print out number, flush for proper output sequencing when output
         is not a terminal. */
      printf("Parent: %lu\n", c);
      fflush(stdout);

      c += 2; /* Increment counter */

      kill(cpid, READY_SIGNAL); /* Wake up child process */

      if (c > n) break; /* Don't go back to sleep if we are done */

      ready = 0; /* Reset ready flag */

      /* Suspend until we receive READY_SIGNAL */
      while (!ready) sigsuspend(&wait_mask);
    };

    wait4(cpid, NULL, 0); /* Don't exist before child finishes */
  }

  return 0;
}

这通过了这些基本测试：

./print_with_signals 100000|sort -n -k 2 -c && echo "Success"
./print_with_signals 100001|sort -n -k 2 -c && echo "Success"

Answer 2

我认为这个家庭作业是给你的，让你尝试很多解决方案，并自己总结信号不是一个好的同步技术。

这是一个宝贵的教训，记住它并使用从现在开始的信号量！：）

使用信号打印奇数偶数

2 个答案: