Question

我试图从一个带有ajax的php文件中获取更多值。

我的代码如下所示：

$.ajax({
    type: "GET",
    url: "phpfile.php",
    success: function (value1,value2,value3,value4,value5,value6) {
        $("#lga").html('<img src="' + value1 + '" alt="image" width="115" height="115"></src>');
        $("#lg").text(value2);
        $("#lgi").text(value3);
        $("#lgv").text(value4);
        $("#lgc").text(value5);
        $("#lt").text(value6);
    }
});

在php中我有6 echo：

<?php
    $game = fetchinfo("value","info","name","current_game");
    $lastwinner = fetchinfo("userid","games","id",$game-1); 
    $winneravatar = fetchinfo("avatar","users","steamid",$lastwinner); 
    $chance = fetchinfo("percent","games","id",$game-1); 
    $items = fetchinfo("itemsnum","games","id",$game-1); 
    $ticket = fetchinfo("winticket","games","id",$game-1); 
    $value = round(fetchinfo("cost","games","id",$game-1),2); 
    $winnername = fetchinfo("winner","games","id",$game-1); 
    echo $winneravatar; 
    echo $game-1; 
    echo $items; 
    echo $value; 
    echo $chance; 
    echo round($ticket*100,7); 
    echo $winnername; 
?>

Answer 1

为什么不用ajax传递数组？就像在PHP代码中创建一个数组，并以编码形式传递它，例如。

sudo arp -d <specific IP address>

比用html格式再次用echo json_encode($arrResult);解析它。

例如。 ajax请求您参考

parseJSON()

在phpfile.php中，你的数组应该是

    $.ajax({
        type: "POST",
        url: "phpfile.php",
        }).done(function( msg ) {
            //alert(msg);
            msg = $.trim( msg );
            if(msg != '[]'){
                var obj = jQuery.parseJSON(msg);

                $("#lga").html('');
                $("#lg").text(obj.value2);
                $("#lgi").text(obj.value3);
                $("#lgv").text(obj.value4);
                $("#lgc").text(obj.value5);
                $("#lt").text(obj.value6);
        }// if 

 });

使用$ .ajax从php获取更多值

1 个答案: