我已经实现了一个Singleton类“SingleTaskExecutor”,它使用SingleThreadExecutor按顺序一次执行一个任务。此类用于按时和按顺序执行异步数据库操作。一切都很好。但是现在我们有一个用例,我们需要暂停此服务一段时间,执行一些操作,然后恢复服务。不确定如何暂停/恢复服务。这是我的代码:
public class SingleTaskExecutor {
private SingleTaskExecutor() {}
private final ExecutorService executor = Executors.newSingleThreadExecutor();
private static class LazyHolder {
private static final SingleTaskExecutor instance = new SingleTaskExecutor();
}
public static SingleTaskExecutor getInstance() {
return LazyHolder.instance;
}
public <T> Task<T> create(Callable<T> callable) {
Task<T> task = new Task<T>() {
@Override
protected T call() throws Exception {
return callable.call();
}
};
return task;
}
public <T> T execute(Task<T> task) {
return (T) executor.submit(task);
}
public void shutDown() {
executor.shutdown();
}
public void awaitTermination() {
try {
executor.awaitTermination(5, TimeUnit.SECONDS);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
public void waitPlease() {
try {
Thread.currentThread().wait();
//executor.wait();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public void resume() {
Thread.currentThread().notifyAll();
//executor.notifyAll();
}
}
答案 0 :(得分:0)
如果我理解正确,您希望暂停执行任务,然后执行一些显式任务,然后恢复它。我实际上看到了以下解决方案:
private volatile boolean paused;
public <T> T execute(Task<T> task) {
if(paused) {
synchronized(this) {
if(paused) {
wait();
}
}
}
return (T) executor.submit(task);
}
public synchronized void waitPlease() {
paused = true;
}
public synchronized void resume() {
paused = false;
notify();
}