我有一个TextView,一个EditView和一个Submit按钮以及一个下一个按钮。在我的资源文件中,我有3个字符串数组。如果我在EditText中的答案是第一个字符串数组的正确答案,我想转到第二个字符串数组(下一个按钮)。再次,如果我在EditText中的答案是第二个字符串数组的正确答案,我想转到第三个字符串数组(下一个按钮),依此类推。以下是我的代码。怎么可能这样做。在person2之后,它返回到person1。这样做的更好方法是什么?有人可以提供一个例子。感谢。
//字符串阵列
<string-array name="person1">
<item>He wore a black hat</item>
<item>He's six feet tall</item>
<item>He went to Harvard</item>
<item>Moon</item>
</string-array>
<string-array name="person2">
<item>She has a cooking show</item>
<item>Her dogs name is Max</item>
<item>She drives a red car</item>
</string-array>
<string-array name="person3">
<item>He first appeared on a drama</item>
<item>He's a friend of yours</item>
<item>His hair is red</item>
</string-array>
// MainActivity
public class MainActivity extends AppCompatActivity {
int mCounter= 0;
int aCount = 0;
int bCount = 0;
TextView myTv;
Button nextBtn;
Button submitBtn;
EditText msg;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
nextBtn = (Button)findViewById(R.id.nextBtn);
myTv = (TextView)findViewById(R.id.myTv);
msg = (EditText)findViewById(R.id.msg);
final String[]person1 = getResources().getStringArray(R.array.person1);
final String[]person2 = getResources().getStringArray(R.array.person2);
final String[]person3 = getResources().getStringArray(R.array.person3);
nextBtn.setOnClickListener(
new View.OnClickListener() {
@Override
public void onClick(View v) {
myTv.setText(person1[mCounter]);
if (mCounter < person1.length -1){
mCounter++;
}else {
mCounter = 0;
}
if(msg.getText().toString().trim().toLowerCase().equals("MARK".toString().trim().toLowerCase())){
myTv.setText(person2[aCount]);
if (aCount < person2.length -1){
aCount++;
}else {
aCount = 0;
}
if (msg.getText().toString().trim().toLowerCase().equals("Susan".toString().trim().toLowerCase())){
myTv.setText(person3[bCount]);
if (bCount < person3.length -1){
bCount++;
}else {
bCount = 0;