WHERE
E.CNO IN
(
SELECT
CNO
FROM
COURSE
WHERE
LOWER(CNAME) LIKE LOWER('%WORLD%')
AND
LOWER(CNAME) LIKE LOWER('%HISTORY%')
)
AND
C.DNAME IN
(
SELECT
DNAME
FROM
COURSE
WHERE
LOWER(CNAME) LIKE LOWER('%WORLD%')
AND
LOWER(CNAME) LIKE LOWER('%HISTORY%')
);
这给了我正在寻找的结果,但我有点强迫症,并希望能够在可能的情况下缩短它。贝娄是我想做的,但我不确定操作员是否会工作。
WHERE
E.CNO, C.DNAME IN
(
SELECT
CNO,
DNAME
FROM
COURSE
WHERE
LOWER(CNAME) LIKE LOWER('%WORLD%')
AND
LOWER(CNAME) LIKE LOWER('%HISTORY%')
);
答案 0 :(得分:2)
某些数据库支持import UIKit
class ViewController: UIViewController {
@IBOutlet weak var scoreLabel: UILabel!
var points: Int = 0
var tickCount=0
var spawnRate=100 // Spawn every 10 seconds to start with
var spawnTimer:NSTimer!
override func viewDidLoad() {
super.viewDidLoad()
self.tickCount=self.spawnRate
self.spawnTimer=NSTimer.scheduledTimerWithTimeInterval(0.1, target: self, selector: Selector("tick"), userInfo: nil, repeats: true)
}
func tick() {
if (--tickCount == 0) {
self.spawnEnemy()
self.spawnRate=spawnRate - 2 // Change this to determine how quickly the spawn rate increases
self.tickCount=self.spawnRate
}
}
子句中的多个列。但是,您可能会发现可以使用in
或join
重写它。以下是exists
:
exists
或者您可以使用where exists (
select 1
from course
where e.cno = course.cno and
c.dname = course.dname and
lower(c.cname) like lower('%WORLD%') and
lower(c.cname) like lower('%HISTORY%')
)
:
join
那里不需要子查询。