Question

As the title suggests, I have code for a Fibonacci series and my goal is to replace multiples of numbers (3, 5, 7 and combinations of them) in the series with a word. I was suggested to use a flag in my if loop to check for the printed phrase, and if the phrase is printed, to skip that number. Essentially, what I want the output to look like is:

1 1 2 skip 8 13 skip 34 55

(this is replacing multiple of three only, for now).

Instead, what I am getting is:

1 1 2 3 skip5 8 13 21 skip34 55

Here is my code as of now:

Any and all help is appreciated!

Answer 1

让我们浏览一下您提供的代码，并尝试理解它为什么不起作用。

//The first thing we do is setup the loop to iterate through the fib numbers.
//This looks good.
for (int i = 0; i < febCount; i++) {
 //Here we print out the fibonacci number we are on, unconditionally.
 //This means that every fibonacci number will be printed no matter what number it is
 //we don't want that.
 System.out.print(feb[i] + ((i % 10 == 9) ? "\n" : " "));
 //After we print the number, we check to see if it is a multiple of three.
 //maybe we should be waiting to print until then?
 if (feb[i] % 3 == 0)
  System.out.print("skip");
}

现在我们已经完成了代码，我们可以提出一个新的解决方案。让我们尝试更新循环，以便它等待打印斐波那契数字，直到我们检查它是否符合我们的条件。

for (int i = 0; i < febCount; i++) {
    if (feb[i] % 3 == 0 || feb[i] % 5 == 0 || feb[i] % 7 == 0) { //check if multiple of 3 5 or 7
         System.out.println(" Skip ");
    } else { //if it's not a multiple, then print the number
       System.out.println(" " + feb[i]);
    }
}

Replacing Multiples of numbers in Fibonacci series using Flag method

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