检查所有数组没有foreach语句

Question

如何检查数据库中是否找不到页面信息？如果我使用foreach检查页面是否存在，我将返回false，如下例所示：

我的路由器文件：

$db = new PDO('mysql:host=127.0.0.1;dbname=project1', 'root', '');
$GetDirectory = $db->prepare('
    SELECT *
    FROM pages
');
$GetDirectory->execute();
$GetDirectory = $GetDirectory->fetchAll(PDO::FETCH_ASSOC);

if (Route::Request_URL()=='/') {
    Route::Navigate_URL('home');
} else {
    foreach ($GetDirectory as $Directory) {
        switch (Route::Request_URL()) {
            case strpos(Route::Request_URL(), $Directory['request']) :
                if (Route::Verify_URL($Directory['pos1'], $Directory['pos2'], $Directory['request'])!==false) {
                    Route::Navigate_URL($Directory['name']);
                    $db = null;
                } else {
                    //this will give an error for each time it didn't found
                }
                break;
        }
    }
}

我的班级档案：

class Route {
    public static function Request_URL() {
        return $_SERVER['REQUEST_URI'];
    }
    public static function Verify_URL($pos1, $pos2, $url) {
        if (strpos(substr(Route::Request_URL(), $pos1, $pos2), $url)!==false) {
            return true;
        } else {
            return false;
        }
    }
    public static function Navigate_URL($RequestURL) {
        $db = new PDO('mysql:host=127.0.0.1;dbname=project1', 'root', '');
        $ListDirectory = $db->prepare('
            SELECT *
            FROM pages
        ');
        $ListDirectory->execute();
        $ListDirectory = $ListDirectory->fetchAll(PDO::FETCH_ASSOC);
        foreach ($ListDirectory as $Directory) {
            switch ($RequestURL) {
                case $Directory['name'] :
                    return require_once SERVE_PATH.$Directory['path'];
                    break;
            }
        }
    }
}

很抱歉长代码。想问一个更简单的问题，但不知道如何解释。