我想像这样解析json对象:
{
"Count" : 1,
"Data" : [
{
"ContactID" : 1567993182,
"Email" : "enamdimensi@localhost.com",
"Action" : "unsub",
"Name" : "",
"Properties" : {}
}
],
"Total" : 1
}
到这个java对象。
public class Response {
@JsonProperty("Status")
private String status;
@JsonProperty("Data")
private List<DataResponse> data;
@JsonProperty("Total")
private Integer total;
@JsonProperty("Count")
private Integer count;
public MailjetResponse() {
super();
}
........ setter and getter .......
}
class DataResponse {
@JsonProperty("ContactID")
private String contactId;
@JsonProperty("Name")
private String name;
@JsonProperty("Email")
private String email;
@JsonProperty("Action")
private String action;
@JsonProperty("Properties")
private Map<String, Object> properties;
public DataResponse() {
super();
}
....... setter and getter .....
}
我用杰克逊做到了,这是我的代码:
final ObjectMapper mapper = new ObjectMapper();
MailjetResponse response = mapper.readValue(content, Response.class);
但是,如果我调试响应,则所有字段Response都为null。
response [Status=null, Data=null, Total=null, Count=null]
我的代码有问题吗?
更新代码: 响应等级
public class Response {
@JsonProperty("Status")
private String status;
@JsonProperty("Data")
private List<DataResponse> data;
@JsonProperty("Total")
private Integer total;
@JsonProperty("Count")
private Integer count;
public String getStatus() {
return status;
}
public void setStatus(String status) {
this.status = status;
}
public Integer getTotal() {
return total;
}
public void setTotal(Integer total) {
this.total = total;
}
public Integer getCount() {
return count;
}
public void setCount(Integer count) {
this.count = count;
}
@Override
public String toString() {
return "MailjetResponse [status=" + status + ", data=" + data
+ ", total=" + total + ", count=" + count + "]";
}
}
DataResponse类
public class DataResponse {
@JsonProperty("ContactID")
private String contactId;
@JsonProperty("Name")
private String name;
@JsonProperty("Email")
private String email;
@JsonProperty("Action")
private String action;
@JsonProperty("Properties")
private Map<String, Object> properties;
public String getContactID() {
return contactId;
}
public void setContactID(String contactID) {
contactId = contactID;
}
public String getName() {
return name;
}
public void setName(String name) {
name = name;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
email = email;
}
public String getAction() {
return action;
}
public void setAction(String action) {
action = action;
}
@Override
public String toString() {
return "DataResponse [contactId=" + contactId + ", name=" + name
+ ", email=" + email + ", action=" + action + ", properties="
+ properties + "]";
}
}
结果是这样的bocome:
response MailjetResponse [status=null, data=[DataResponse [contactId=1567993182, name=null, email=null, action=null, properties={}]], total=1, count=1]
答案 0 :(得分:1)
问题在于你的制定者。
public void setEmail(String email) {
email = email;
}
这使得输入arg email
到输入arg email
(而不是字段this.email
)的非限定分配。
它应该是:
public void setEmail(String email) {
this.email = email;
}
杰克逊使用setter,除非另有配置。更正设置器(例如,使用IDE自动生成它们)或删除它们并仅使用字段。为此,要么使用
注释类@JsonAutoDetect(fieldVisibility = Visibility.ANY, getterVisibility = Visibility.NONE, setterVisibility = Visibility.NONE)
public class DataResponse {
或更改映射器设置,例如
ObjectMapper mapper = new ObjectMapper();
mapper.setVisibilityChecker(mapper.getSerializationConfig().getDefaultVisibilityChecker()
.withFieldVisibility(JsonAutoDetect.Visibility.ANY)
.withGetterVisibility(JsonAutoDetect.Visibility.NONE)
.withSetterVisibility(JsonAutoDetect.Visibility.NONE)
.withCreatorVisibility(JsonAutoDetect.Visibility.NONE));
另外:如果您更正了setter,您可以删除字段注释...选择最适合您的用例的内容。我更喜欢我的杰克逊序列化只使用字段,总是注释 - 或mixins。
答案 1 :(得分:1)
I have tried your example and used setter only and got email field populated after deserialisation of json.I could not see any other issue.
Below is the code I have tried :
public class Response {
@JsonProperty("Status")
private String status;
@JsonProperty("Data")
private List<DataResponse> data;
@JsonProperty("Total")
private Integer total;
@JsonProperty("Count")
private Integer count;
public void setStatus(String status) {
this.status = status;
}
public void setData(List<DataResponse> data) {
this.data = data;
}
public void setTotal(Integer total) {
this.total = total;
}
public void setCount(Integer count) {
this.count = count;
}
}
public class DataResponse {
@JsonProperty("ContactID")
private String contactId;
@JsonProperty("Name")
private String name;
@JsonProperty("Email")
private String email;
@JsonProperty("Action")
private String action;
@JsonProperty("Properties")
private Map<String, Object> properties;
public void setContactId(String contactId) {
this.contactId = contactId;
}
public void setName(String name) {
this.name = name;
}
public void setEmail(String email) {
this.email = email;
}
public void setAction(String action) {
this.action = action;
}
public void setProperties(Map<String, Object> properties) {
this.properties = properties;
}
}
final ObjectMapper mapper = new ObjectMapper();
mapper.disable(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES);
final Response response = mapper.readValue(message(), Response.class);
我更喜欢在构造函数上注释Jsoncreator。