如何在程序初始化时禁用btnExecute JButton
?
之后,当三个JComboBox
个选定项目不等于"选择..."项目,启用此按钮
此问题的第二部分已解决,但在启动程序时启用该按钮,如果三个JButton
不等于"则应解析为仅允许JComboBox
。选择......"项目
这是我的代码:
public class WebStarter_v2 {
private JFrame frame;
private JComboBox<Object> cbProgram;
private JComboBox<Object> cbVersion;
private JComboBox<Object> cbAction;
private JButton btnExecute;
private boolean programSelected = false;
private boolean versionSelected = false;
private boolean actionSelected = false;
private String prototypeValue="XXXXXXXXXX";
private String[] programs = {"Choose...", "Apache", "PHP-FPM", "MySQL"};
private String[] actions = {"Choose...", "start", "restart", "stop"};
//private String[] status = {"standby", "running", "stopped", "error"};
private String[] apacheVersions = {"Choose...", "2.2.31", "2.4.17"};
private String[] phpVersions = {"Choose...", "5.6.16", "7.0.0"};
private String[] mysqlVersions = {"Choose...", "5.7.9"};
public static void main(String[] args) {...}
public WebStarter_v2() {
initialize();
}
private void initialize() {
...
JPanel panel_Actions = new JPanel();
splitPane.setTopComponent(panel_Actions);
...
...
cbProgram = new JComboBox<Object>(new DefaultComboBoxModel<Object>(programs));
cbProgram.setPrototypeDisplayValue(prototypeValue);
cbProgram.addItemListener(new ItemListener() {
@Override
public void itemStateChanged(ItemEvent event) {
if(event.getStateChange() == ItemEvent.SELECTED){
String item = event.getItem().toString();
if ( item.contains("Apache") ){
makeComboBoxModel(cbVersion, apacheVersions);
programSelected = true;
updateButtonState();
}
else if ( item.contains("PHP-FPM") ){
makeComboBoxModel(cbVersion, phpVersions);
programSelected = true;
updateButtonState();
}
else if ( item.contains("MySQL") ){
makeComboBoxModel(cbVersion, mysqlVersions);
programSelected = true;
updateButtonState();
}
else
{
programSelected = false;
//set initial state of cbVersion and cbAction
cbVersion.setModel(new DefaultComboBoxModel<Object>());
cbAction.setModel(new DefaultComboBoxModel<Object>());
updateButtonState();
}
}
}
});
...
...
cbVersion = new JComboBox<Object>();
cbVersion.setPrototypeDisplayValue(prototypeValue);
cbVersion.addItemListener(new ItemListener() {
@Override
public void itemStateChanged(ItemEvent event) {
if(event.getStateChange() == ItemEvent.SELECTED){
String item = event.getItem().toString();
if ( !item.contains("Choose...") )
{
versionSelected = true;
makeComboBoxModel(cbAction, actions);
updateButtonState();
}
else{
versionSelected = false;
cbAction.setModel(new DefaultComboBoxModel<Object>());
updateButtonState();
}
}
}
});
...
...
cbVersion = new JComboBox<Object>();
cbVersion.setPrototypeDisplayValue(prototypeValue);
cbVersion.addItemListener(new ItemListener() {
@Override
public void itemStateChanged(ItemEvent event) {
if(event.getStateChange() == ItemEvent.SELECTED){
String item = event.getItem().toString();
if ( !item.contains("Choose...") )
{
versionSelected = true;
makeComboBoxModel(cbAction, actions);
updateButtonState();
}
else{
versionSelected = false;
cbAction.setModel(new DefaultComboBoxModel<Object>());
updateButtonState();
}
}
}
});
...
...
cbAction = new JComboBox<Object>();
cbAction.setPrototypeDisplayValue(prototypeValue);
cbAction.addItemListener(new ItemListener() {
@Override
public void itemStateChanged(ItemEvent event) {
if(event.getStateChange() == ItemEvent.SELECTED){
String item = event.getItem().toString();
if ( !item.contains("Choose...") ){
actionSelected = true;
updateButtonState();
}
else{
actionSelected = false;
updateButtonState();
}
}
}
});
...
...
btnExecute = new JButton("Execute");
...
...
JPanel panel_Messages = new JPanel();
splitPane.setBottomComponent(panel_Messages);
}
答案 0 :(得分:3)
您需要JButton
的{{3}}方法:
btnExecute.setEnabled(false);
之后,当您的用户选择三个JComboBox
时,您可以将其设置回true
。
答案 1 :(得分:1)
或者你可以setVisible()
为此:
btnExecute.setVisible(false);
然后在每个JComboBox的addItemListener
中,您应该检查programSelected
,versionSelected
和ActionSelected
。如果所有这些都是true
,请制作
btnExecute.setVisible(true);