Question

我正在从shell脚本

调用

let f4 (processOptions:ProcessOptions) = 
    processOptions.func1.Invoke 4 |> ignore
    processOptions.func2.Invoke "abc" |> ignore

f4 { func1 = f1; func2 = f1 }

，如下所示

myAwk.awk

awk -f myAwk.awk -v inputKeyword="SEARCH" file2.xml

如何在我所需的位置提供$bash: cat myAwk.awk BEGIN{ print "This is from awk script:" inputKeyword; //This prints SEARCH string. Fine. } /<record / { i=1 } i { a[i++]=$0 } /<\/record>/ { if (found) { for (i=1; i<=length(a); ++i) print a[i] >> resultFile.xml } i=0; found=0 } /<keyword>inputKeyword<\/keyword>/ { found=1 } //Looks like the value for inputKeyword is not available here. //There are no errors though.的价值？

Answer 1

根据手册页，您应该在-f之前传递选项：

SYNOPSIS

   `gawk [ POSIX or GNU style options ] -f program-file [ -- ] file ...`
   `gawk [ POSIX or GNU style options ] [ -- ] program-text file ...`

Answer 2

您需要更改行

/<keyword>inputKeyword<\/keyword>/ { found=1 }

到

$0 ~ "<keyword>"inputKeyword"</keyword>" { found=1 }

如果匹配模式（//）在变量中，则不需要regex。 awk无法插入//之间的内容。它将被视为一个字符串。

awk：无法访问传递的参数

2 个答案: