原始SQL查询:
SELECT *
FROM
(SELECT p.id,
p.title,
p.mark,
(SELECT max(created)
FROM comments c
WHERE c.post_id=p.id
AND c.mark=1) AS latest_at
FROM posts p) AS Post
WHERE Post.latest_at IS NOT NULL
ORDER BY latest_at DESC LIMIT 10
我有这两个表:
$postsTable = TableRegistry::get('Posts');
$comments = TableRegistry::get('Comments');
我用cakephp-3方式做了内部查询:
SELECT p.id,
p.title,
p.mark,
(SELECT max(created)
FROM comments c
WHERE c.post_id=p.id AND c.mark=1) AS latest_at
FROM posts p
Cakephp-3方式内部sql与cakephp-3 querybuilder(下面的查询是否正确?):
$subquery = $comments->find();
$subquery->select([$subquery->func()->max('created')])
->from(['c'=>'comments'])
->where(['c.post_id=p.id','mark=1']);
$pquery = $postsTable->find()
->select(['p.id','p.title','p.mark','latest_at'=>$subquery])
->from(['p'=>'posts']);
如何以cakephp-3方式编写外部选择查询? (select * from(derived table))
提前致谢。任何答案都将受到高度赞赏。
答案 0 :(得分:3)
要直接回答您的问题,这是如何在另一个查询的from部分中使用子查询:
$query = $this->MyTable->connection()->newQuery();
$query->select('*')->from(['Post' => $subqueryObject])->fetchAll('assoc');
这将返回结果数组,如果你知道它应该保持什么类型的实体,那么这样做:
$query = $this->Posts
->find()
->select($listOfFields)
->from(['Posts' => $subqueryObject], true)
->toArray();
答案 1 :(得分:1)
对于一个非常简单的问题(即获得最新评论的帖子),这是一个非常复杂的解决方案。
更好的查询是:
select posts.* from posts join comments on (comments.post_id = posts.id) group by posts.id order by comments.created desc limit 1
执行此查询的ORM方式是:
$post = $postsTable
->find()
->select(['Posts.id', 'Posts.title', 'Posts.mark', 'Comments.created'])
->leftJoinWith('Comments', function ($q) {
return $q->where(['Comments.mark' => true]);
}))
->group(['Posts.id'])
->order(['Comments.created' => 'desc'])
->first();
答案 2 :(得分:-1)
对于特殊情况,cakephp允许您编写RAW SQL并保持在cakephp方式内。只需在模型中创建一个函数,您就可以通过将查询放在$this->query("...")
中来编写该查询。
示例(模型中):
public function getPosts(){
$this->query("SELECT * FROM Posts AS Post"); //put complext query here
}
然后在Controller:
$posts = $this->Post->getPosts();