Question

这是我想要使用的json数据：

{
     "name" : "Ravi Tamada", 
     "email" : "ravi8x@gmail.com",
     "phone" : 
      {
         "home" : "08947 000000",
         "mobile" : "9999999999"
      }

}

这是我的JsonObjectRequest：

JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, APITEST,null, new Response.Listener<JSONObject>() {

        @Override
        public void onResponse(JSONObject jsonObject) {

            Gson gson = new Gson();
            People people;
            people = gson.fromJson(jsonObject.toString(),People.class);
            tv_city.setText(""+people.email);

        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError volleyError) {



        }
    });

可以使用tv_city.setText（＆＃34;＆＃34; + people.email（））...

这是我的javabean类：

public class People {

    public String name ;
    public String email;

    public class Phone{
        public String home;
        public String mobile;

    }

}

现在我想得到＆＃34; home＆＃34;数，如何？

Answer 1

1-您必须按如下方式更新您的bean类： -

public class People implements Serializable {
private String name ;
private String email;
private Phone phone;

 public Phone getPhone () {
    return phone;
}

public void setPhone (Phone phone) {
    this.phone = phone;
}
public String getName () {
    return name;
}

public void setName (String name) {
    this.name = name;
}

public String getEmail () {
    return email;
}

public void setEmail (String email) {
    this.email = email;
}}

2-创建一个新的bean类Phone.java： -

public class Phone implements Serializable{
private String home;

public String getMobile () {
    return mobile;
}

public void setMobile (String mobile) {
    this.mobile = mobile;
}

public String getHome () {
    return home;
}

public void setHome (String home) {
    this.home = home;
}

private String mobile;}

3-现在按如下方式更新您的代码： -

JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, APITEST,null, new Response.Listener<JSONObject>() {

    @Override
    public void onResponse(JSONObject jsonObject) {

        Gson gson = new Gson();
        People people;
        people = gson.fromJson(jsonObject.toString(),People.class);
        tv_city.setText(""+people.email);
        //for getting Home & Mobile number
          String home=people.getPhone.getHome();
          String mobile=people.getPhone.getMobile();

    }
}, new Response.ErrorListener() {
    @Override
    public void onErrorResponse(VolleyError volleyError) {



    }
});

注意： - 我的上面的bean是你问题中预期的api响应。但是如果您有嵌套对象，则必须在People bean中选择List<Phone>或ArrayList<Phone>，然后创建其getter和setter。

希望这会对你有帮助!!!

Answer 2

您也可以直接从json对象获取数据，如

if(JsonObject!=null){
String email=JsonObject.getString("email");
}

或
要使其工作在模型对象（人物对象）中编写getters（）和setters（），您也可以自动生成它。一旦你这样做了这样的数据

JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, APITEST,null, new Response.Listener<JSONObject>() { @Override public void onResponse(JSONObject jsonObject) { Gson gson = new Gson(); People people; people = gson.fromJson(jsonObject.toString(),People.class); tv_city.setText(""+people.getEmail()); } }, new Response.ErrorListener() { @Override public void onErrorResponse(VolleyError volleyError) { } });

Answer 3

用

替换您的JavaBean类

public class People {

@SerializedName("name")
@Expose
private String name;
@SerializedName("email")
@Expose
private String email;
@SerializedName("phone")
@Expose

private Phone phone;

/**
* 
* @return
* The name
*/
public String getName() {
return name;
}

/**
* 
* @param name
* The name
*/
public void setName(String name) {
this.name = name;
}

/**
* 
* @return
* The email
*/
public String getEmail() {
return email;
}

/**
* 
* @param email
* The email
*/
public void setEmail(String email) {
this.email = email;
}

/**
* 
* @return
* The phone
*/
public Phone getPhone() {
return phone;
}

/**
* 
* @param phone
* The phone
*/
public void setPhone(Phone phone) {
this.phone = phone;
}

}

并且

public class Phone {

@SerializedName("home")
@Expose
private String home;
@SerializedName("mobile")
@Expose
private String mobile;

/**
* 
* @return
* The home
*/
public String getHome() {
return home;
}

/**
* 
* @param home
* The home
*/
public void setHome(String home) {
this.home = home;
}

/**
* 
* @return
* The mobile
*/
public String getMobile() {
return mobile;
}

/**
* 
* @param mobile
* The mobile
*/
public void setMobile(String mobile) {
this.mobile = mobile;
}

}

然后你可以在你的JsonResponse中调用

JSONObject phone=jsonObject.getJSONObject("phone");

String home=phone.getHome();

将返回主页号码。

希望有所帮助：）

Answer 4

JSONObject phone=jsonObject.getJSONObject("phone");

String home=phone.getString("home");

现在家庭电话号码中有家庭电话号码。

如何使用gson和volley解析嵌套的json？

4 个答案: