Question

我正在进行python刻字作业 90或更高版本是A，依此类推等等其他字母等级;但是当一个值作为负数输入时，我需要代码除了显示error之外什么都不做。

这是我到目前为止所尝试的：

#Design a Python program to assign grade to 10 students
#For each student, the program first asks for the user to enter a positive number
#A if the score is greater than or equal to 90
#B if the score is greater than or equal to 80 but less than 90
#C if the score is greater than or equal to 70 but less than 80
#D if the score is greater than or equal to 60 but less than 70
#F is the score is less than 60
#Ihen the program dispalys the letter grade for this student.
#Use while loop to repeat the above grade process for 10 students.

keep_going = 'y'

while keep_going == "y":

            num = float(input("Enter a number: "))
            if num >= 90:
                print("You have an A")
            elif num >= 80:
                print("You have an 3")
            elif num >= 70:
                print("You have an C")
            elif num >= 60:
                print("You have an D")
            elif (num < 60 and <= 0:
                print ("You have an F")

            else:
                print("lnvalid Test Score.")

Original screenshot

Answer 1

我看到三个问题，都在同一行：

elif (num < 60 and <= 0:

语法：num < 60 and <= 0不是有效的表达式;应为num < 60 and num <= 0
逻辑：num <= 0不是您想要的，应该是num >= 0
语法：您错过了结束括号)。

如果你改变它们，它应该有效。

Answer 2

grade = int(input("Enter Score:"))
print "FFFFFDCBAA"[grade//10] if grade >= 0 else "ERROR!!!!"

Answer 3

你只需将你的elif改为60以下。

keep_going = 'y'

while keep_going == "y":

        num = float(input("Enter a number: "))
        if num >= 90:
            print("You have an A")
        elif num >= 80:
            print("You have an 3")
        elif num >= 70:
            print("You have an C")
        elif num >= 60:
            print("You have an D")
        elif 60 > num >= 0:
            print ("You have an F")
        else:
            print("lnvalid Test Score.")

python：评分，负值

3 个答案: