我必须从多个属性返回类似string.Concat的CallerAddress属性,除非它们不为null。到目前为止,我已经尝试过这个,但是没有用。映射后,我的CallerAddress等于“Str.SomeStreetName”。我抬头查看了我的数据库,并且我对其他列有了价值。那么,我怎样才能使这个工作?
Mapper.CreateMap<ClientRecordingsDao,ClientRecording>()
.ForMember(x => x.CallerAddress,
b =>
b.MapFrom(
x => x.CallerStreet != String.Empty
? "Str." + x.CallerStreet
: String.Empty +
x.CallerStreetNumber != String.Empty
? " Nr."
: String.Empty + x.CallerStreetNumber +
x.CallerBuilding != String.Empty
? " Bl."
: String.Empty + x.CallerBuilding +
x.CallerApartment != String.Empty
? " Ap."
: String.Empty + x.CallerApartment))
答案 0 :(得分:1)
它将+
操作符应用于错误的位置。在()
:
Mapper.CreateMap<ClientRecordingsDao,ClientRecording>()
.ForMember(x => x.CallerAddress, b => b.MapFrom(
x => (x.CallerStreet != String.Empty ? "Str." + x.CallerStreet : String.Empty) +
(x.CallerStreetNumber != String.Empty ? " Nr." + x.CallerStreetNumber : String.Empty) +
(x.CallerBuilding != String.Empty ? " Bl." + x.CallerBuilding : String.Empty) +
(x.CallerApartment != String.Empty ? " Ap." + x.CallerApartment : String.Empty)));
您的代码映射到:
Mapper.CreateMap<ClientRecordingsDao,ClientRecording>()
.ForMember(x => x.CallerAddress, b => b.MapFrom(
x => x.CallerStreet != String.Empty ? "Str." + x.CallerStreet :
(String.Empty + x.CallerStreetNumber != String.Empty ? " Nr." + x.CallerStreetNumber :
(String.Empty + x.CallerBuilding != String.Empty ? " Bl." + x.CallerBuilding :
(String.Empty + x.CallerApartment != String.Empty ? " Ap." + x.CallerApartment : String.Empty)))));