我的问题是我有多个触发不同轮播的图标。默认情况下,第一个轮播是可见的,其余的是隐藏的。这是图标(织物样本,在我的例子中):
<div id="home" class="fabrics">
<h2>Fabrics Available</h2>
<a class="charcoal" href="javascript:void(0)">
<div class="magnify-3">
<div class="large-zoom-3"></div>
<img class="small-zoom-3" src="<?php echo $this->getSkinUrl('images/recliners/fabrics/charcoal.png');?>" alt="Charcoal" />
</div>
</a>
<a class="mushroom" href="javascript:void(0)">
<div class="magnify-2">
<div class="large-zoom-2"></div>
<img class="small-zoom-2" src="<?php echo $this->getSkinUrl('images/recliners/fabrics/mushroom.png');?>" alt="Mushroom" />
</div>
</a>
</div>
这是我的旋转木马:
<div class="imgs slider charcoal">
<img src="<?php echo $this->getSkinUrl('images/recliners/indiana/charcoal-1.png');?>" alt="Charcoal" />
<img src="<?php echo $this->getSkinUrl('images/recliners/indiana/charcoal-2.png');?>" alt="Charcoal" />
<img src="<?php echo $this->getSkinUrl('images/recliners/indiana/charcoal-3.png');?>" alt="Charcoal" />
</div>
<div class="imgs slider mushroom" style="display:none">
<img src="<?php echo $this->getSkinUrl('images/recliners/indiana/mushroom-1.png');?>" alt="Mushroom" />
<img src="<?php echo $this->getSkinUrl('images/recliners/indiana/mushroom-2.png');?>" alt="Mushroom" />
<img src="<?php echo $this->getSkinUrl('images/recliners/indiana/mushroom-3.png');?>" alt="Mushroom" />
</div>
和我的Javascript:
jQuery(document).ready(function() {
jQuery(".fabrics a").click(function() {
var e = jQuery(this).attr("class");
jQuery(".imgs").hide(), jQuery(".imgs." + e).toggle();
})
}),
jQuery(document).ready(function() {
jQuery(".slider").owlCarousel({
loop: !0,
autoplay: !0,
autoplayTimeout: 3e3,
autoplayHoverPause: !0,
items: 1,
animateIn: "fadeIn",
animateOut: "fadeOut",
navigation: !0
})
});
单击第二个项目时,它会加载第二个轮播,但width
似乎很大。我的情况1260px
。我理解这可能是因为浏览器不知道width
并且第二个轮播被设置为不显示?有没有办法可以在我的某个图标的click
事件上触发刷新?
答案 0 :(得分:1)
而不是隐藏将轮播放在高度为0的包装元素内;并且溢出隐藏;要将其切换到可见的设置高度:auto;