Question

我必须在服务器端发送三个不同的图像。现在一个图像上传了三次。但我选择了三种不同的图像。
因为我给了count = 0.然后它需要第一张图片然后发送第一张图片三次到服务器。
如果我给count = 1那么第二张图片需要三次发送一次到服务器。
我不知道如何计算0,1和2一次发送三个图像。所以我可以一次发送三个图像将其发送到服务器。

logcat的：

02-11 04:32:20.565: E/params[0](16395): 0
02-11 04:32:20.582: E/ParamsArray(16395): [0, pk0.jpg]

MainActivity.java：

  public class MainActivity extends Activity {

    private Button upload, pick;
    MultipartEntity entity;
    GridView gv;
    int count = 0;
    public ArrayList<String> map = new ArrayList<String>();
    Bundle b;
    TextView noImage;


   @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

     upload.setOnClickListener(new View.OnClickListener() {

            public void onClick(View v) {
                new ImageUploadTask().execute(count + "", "pk" + count + ".jpg");

                /*Log.e("url", url);
                new UserProfileUpdateAsynTask().execute(url);*/
            }
        });
}

class ImageUploadTask extends AsyncTask<String, Void, String> {


        ProgressDialog dialog;
        String url = "";

        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            dialog = new ProgressDialog(MainActivity.this);
            dialog.setMessage("Loading...");
            dialog.setCancelable(false);
            dialog.show();
        }

        @Override
        protected String doInBackground(String... params) {

            HttpEntity resEntity;  

            int i = Integer.parseInt(params[0]);
            Log.e("params[0]",""+i);

            Bitmap bitmap = decodeFile(map.get(i));
            HttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(url);
            entity = new MultipartEntity();

            ByteArrayOutputStream bos = new ByteArrayOutputStream();
            bitmap.compress(CompressFormat.JPEG, 100, bos);
            byte[] data = bos.toByteArray();

            try {

                Log.e("ParamsArray",""+Arrays.toString(params));



            entity.addPart("filename[0]", new ByteArrayBody(data,"image/jpeg", params[1]));
            entity.addPart("filename[1]", new ByteArrayBody(data,"image/jpeg", params[1]));
            entity.addPart("filename[2]", new ByteArrayBody(data,"image/jpeg", params[1]));


                httpPost.setEntity(entity);
                HttpResponse response = httpClient.execute(httpPost);
                resEntity = response.getEntity();
                String entityContentAsString = EntityUtils.toString(resEntity);

                return entityContentAsString;

            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }

            return null;

        }

        @Override
        protected void onPostExecute(String result) {
            super.onPostExecute(result);

            if (result != null) {
                dialog.dismiss();
                Log.e("Update_profile", result);

            }
        }

    }



}

任何人都可以帮助我。谢谢。

Answer 1

您发送的文件与您收到相同图片三次的原因相同。看看你的代码

 entity.addPart("filename[0]", new ByteArrayBody(data,"image/jpeg", params[1]));
            entity.addPart("filename[1]", new ByteArrayBody(data,"image/jpeg", params[1]));
            entity.addPart("filename[2]", new ByteArrayBody(data,"image/jpeg", params[1]));

在上面的代码params[1]中引用了同一个文件pk0.jpg。如果你想发送不同的图像，那么你应该做这样的事情

for(int i = 0; i < count; i++) {
entity.addPart("filename[" + i + "]", new ByteArrayBody(data,"image/jpeg", "pk" + i + ".jpg"));
}

希望这有帮助。

Answer 2

entity.addPart("filename[0]", new ByteArrayBody(data,"image/jpeg", params[1]));
entity.addPart("filename[1]", new ByteArrayBody(data,"image/jpeg", params[1]));
entity.addPart("filename[2]", new ByteArrayBody(data,"image/jpeg", params[1]));

您正在发送三次相同的文件，这就是问题所在。

最好将图片路径放在 SharedPrefrence 。

    byte[] data1 = null,data2= null,data3= null;

    if(PreferenceManager.getDefaultSharedPreferences(getBaseContext()).contains("endum_image_0"))
    {       up_image1 = PreferenceManager.getDefaultSharedPreferences(getBaseContext()).getString("endum_image_0", "");
            bitmap = BitmapFactory.decodeFile(up_image1, options1);
            bitmap.compress(CompressFormat.JPEG, 100, bos1);
            data1 = bos1.toByteArray();
    }
    if(PreferenceManager.getDefaultSharedPreferences(getBaseContext()).contains("endum_image_1"))
    {       up_image2 = PreferenceManager.getDefaultSharedPreferences(getBaseContext()).getString("endum_image_1", "");
            bitmap = BitmapFactory.decodeFile(up_image2, options1);
            bitmap.compress(CompressFormat.JPEG, 100, bos2);
            data2 = bos2.toByteArray();
    }

    if(PreferenceManager.getDefaultSharedPreferences(getBaseContext()).contains("endum_image_2"))
    {       up_image3 = PreferenceManager.getDefaultSharedPreferences(getBaseContext()).getString("endum_image_2", "");
            bitmap = BitmapFactory.decodeFile(up_image3, options1);
            bitmap.compress(CompressFormat.JPEG, 100, bos3);
            data3 = bos3.toByteArray();
    }

如果字节数组有数据，则只将其发送到服务器

    if(data1!=null){
    entity.addPart("files[]", new ByteArrayBody(data1,"image/jpeg", "u1.jpg"));
    }
    if(data2!=null){
    entity.addPart("files[]", new ByteArrayBody(data2,"image/jpeg", "u2.jpg"));
    }

    if(data3!=null){
    entity.addPart("files[]", new ByteArrayBody(data3,"image/jpeg", "u3.jpg"));
    }

在服务器上发送数据：

    HttpClient httpClient = new DefaultHttpClient();
    HttpPost httpPost = new HttpPost(url);
    MultipartEntity entity = new MultipartEntity();
    httpPost.setEntity(entity);
    HttpResponse response = httpClient.execute(httpPost);

    BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8"));

    StringBuilder s = new StringBuilder();

    while ((sResponse = reader.readLine()) != null) 
        {
            s = s.append(sResponse);
        }

    if(response.getStatusLine().getStatusCode() == HttpStatus.SC_OK)
    {
        return s.toString();
    }else
    {
        return "{\"status\":\"false\",\"message\":\"Some error occurred\"}";
    }

Answer 3

如果你认为SOLID Principal很好......我会说..而不是在参数中传递字符串..为什么不传递自定义模型数组..这样在将来你可以使用上传器为不同的数据类型..这为您提供了灵活性。

例如

public class Image {
public Bitmap bitmap;
public String dataType;
public String name;
}

而且您可以创建AsynTask，如下所示。

class ImageUploadTask extends AsyncTask<Image, Void, String> {
        ProgressDialog dialog;
        String url = "";

        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            dialog = new ProgressDialog(MainActivity.this);
            dialog.setMessage("Loading...");
            dialog.setCancelable(false);
            dialog.show();
        }

        @Override
        protected String doInBackground(Image... params) {
            HttpEntity resEntity;  
            HttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(url);
            entity = new MultipartEntity();


          try {

            for(int i;i<params.length;i++) {
                ByteArrayOutputStream bos = new ByteArrayOutputStream();
                params[i].bitmap.compress(CompressFormat.JPEG, 100, bos);
                byte[] data = bos.toByteArray();
                entity.addPart("filename["+i+"]", new ByteArrayBody(data,params[i].dataType, params[i].name));
            }




                httpPost.setEntity(entity);
                HttpResponse response = httpClient.execute(httpPost);
                resEntity = response.getEntity();
                String entityContentAsString = EntityUtils.toString(resEntity);

                return entityContentAsString;

            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }

            return null;

        }

        @Override
        protected void onPostExecute(String result) {
            super.onPostExecute(result);

            if (result != null) {
                dialog.dismiss();
                Log.e("Update_profile", result);

            }
        }

    }

将多个图像发送到服务器：一个图像发送三次到服务器问题

3 个答案: