Question

我正在使用DENSE_RANK为每个组[y]中的[x]的不同值分配序号。它添加了一个新列[rank]。

我还想要一个新列，显示每个[y]内的最高等级[x]（最高序列号），例如[highest_rank]。有没有办法同时获取这个新列，而不必为最大值创建一个单独的表，然后将表连接在一起？

SELECT [x],[y],[rank]
INTO table2
FROM
(
SELECT *, DENSE_RANK() OVER (PARTITION BY [x] ORDER BY [y] ) AS [rank]
FROM table1
) tmp

Answer 1

如果我理解正确，你就会找到这样的东西：

;WITH cte1 AS (
    SELECT *,DENSE_RANK() OVER (PARTITION BY [x] ORDER BY [y] ) AS [rank]
    FROM table1 
),
cte2 AS (
    SELECT [x], [highest_rank]=MAX([rank])
    FROM cte1
    GROUP BY [x]
)
SELECT cte1.[x],cte1.[y],cte1.[rank],cte2.[highest_rank]
FROM cte1 INNER JOIN cte2 ON cte2.[x]=cte1.[x];

使用DENSE_RANK的顺序数和最大值

1 个答案: