Question

foo = '/input/directory/'
faa = ['/input/directory/file1.txt', '/input/directory/file2.txt']

我需要从我的列表（faa）和文件扩展名中删除目录名称（即foo），只留下

bar = ['file1', 'file2']

Answer 1

使用map

bar = map(lambda x: '.'.join(x.replace(foo, '').split('.')[:-1]), faa)

Answer 2

试;

Error occurred during initialization of VM (java/lang/NoClassDefFoundError: java/lang/Object)

Answer 3

也许：

try this. 

if ([[[UIDevice currentDevice] systemVersion] floatValue] >= 8.0)
    {
        [[UIApplication sharedApplication] registerUserNotificationSettings:[UIUserNotificationSettings settingsForTypes:(UIUserNotificationTypeSound | UIUserNotificationTypeAlert | UIUserNotificationTypeBadge) categories:nil]];
        [[UIApplication sharedApplication] registerForRemoteNotifications];
    }
    else
    {
        [[UIApplication sharedApplication] registerForRemoteNotificationTypes:
         (UIUserNotificationTypeBadge | UIUserNotificationTypeSound | UIUserNotificationTypeAlert)];
    }

Answer 4

foo = '/input/directory/'
faa = ['/input/directory/file1.txt', '/input/directory/file2.txt']

import os.path

bar = [os.path.splitext(path.replace(foo, ''))[0]
       for path in faa]
print(bar)

或者没有foo：

faa = ['/input/directory/file1.txt', '/input/directory/file2.txt']

from os.path import basename, splitext
bar = [splitext(basename(path))[0]
       for path in faa]
print(bar)

Answer 5

您可以执行以下操作：

import os

foo = '/input/directory/'
faa = ['/input/directory/file1.txt', '/input/directory/file2.txt', '/not/matching/foo/file3.txt']   

faa = [os.path.splitext(os.path.split(f)[1])[0] if f.startswith(foo) else f for f in faa]   
print faa

这会给你以下列表：

['file1', 'file2', '/not/matching/foo/file3.txt']

如果您总是想要文件名，那么：

import os

foo = '/input/directory/'
faa = ['/input/directory/file1.txt', '/input/directory/file2.txt', '/not/matching/foo/file3.txt']   

faa = [os.path.splitext(os.path.split(f)[1])[0] for f in faa]   
print faa

，并提供：

['file1', 'file2', 'file3']

Answer 6

您可以执行以下操作：

SamplerState sam3DPoint
{
    Filter = MIN_MAG_MIP_POINT;
    AddressU = Border;
    AddressV = Border;
    AddressW = Border;
    BorderColor = float4(0, 0, 0, 0);
};

Answer 7

您可以使用re模块和re.findall来实现(?<=)字符串foo后面的积极外观，以及带{} extension的{{1}}到字符串的末尾：

res = [re.findall('(?<={}).+(?=[.].*$)'.format(foo), elem)[0] for elem in faa]

print(res)
['file1', 'file2']

注意：您可以使用regex101.com检查regex表达式

从list - python中删除已定义的字符串

7 个答案: