当函数在Javascript中将其设置为true时，Bool值返回false

Question

我正面临这个问题，在文档准备就绪时创建了一个音频播放器，并且将var作为假播放，但是每次函数似乎都被正确调用但没有将该变量设置为true： 代码是这个函数是从点击监听器调用的。

var cartSongPlayer = new Audio();
var playingStatus = false;
var playingTrack;

function switchTrack(trackID, trackSource) {
    //logging basic information:
    console.log('Current Track ID ' + trackID)
    console.log('Current Track Source ' + trackSource)

    console.log('Previous Track ID ' + playingTrack)
    console.log('Playing Status ' + playingStatus)

    if (playingStatus) {
        console.log('song is playing')
        if (trackID == playingTrack) {
            playingStatus == false;
            console.log('pausing current song')
            cartSongPlayer.pause();

        } else {
            console.log('moved to new song')
            playingStatus == true;
            playingTrack = trackID
            cartSongPlayer.src = trackSource;
            cartSongPlayer.play();
        }
    //no song is playing
    } else {
        console.log('song is not playing')
        if (trackID == playingTrack) {
            playingStatus == true;
            console.log('resumed song')
            cartSongPlayer.play();

        } else {
            console.log('started new song')
            playingStatus == true;
            playingTrack = trackID
            cartSongPlayer.src = trackSource;
            cartSongPlayer.play();
        }
    }
}

Answer 1

您似乎错误地使用了==比较运算符，而不是=赋值运算符。

更改

playingStatus == true;

到

playingStatus = true;

Answer 2

您永远不会更改playingStatus的价值。

==是等于运算符，而不是赋值运算符（=）。