Question

所以我一直在努力解决这个问题。我修复了所有的内存probs（逻辑好几天），现在我被困在看似最简单的东西上。我必须在它们已满时扩展两个数组，这会扩展它们，但是不会复制数据，有关从何处开始的任何建议？

List::List(const List& x, int b)

{

if(b == 1)    // if car needs to grow
{
    size1 = x.size1 * 2;
    car = new Car[size1];
    for(int i = 0; i < count1; i++)
        car[i] = x.car[i];          // what copies .. I think...
}
else if(b == 2)            // if motorcycle array needs to grow
{
    size2 = x.size2 * 2;
    motor = new Motorcycle[size2];
    for(int i = 0; i < count2; i++)
    {
        motor[i] = x.motor[i];   // what copies .. I think...
    }   
}

}

我在这两个类中都有一个asignment运算符重载

Car& Car::operator=( Car x)
{
    this->setModel(x.rModel()); 
    this->setMake(x.rMake());   
    this->setPrice(x.Vehicle::getPrice());
    this->setMileage(x.rMiles());
    this->setLot(x.rLot());
    this->setGas(x.rGas());
    this->seats = x.rSeats();
    this->luxury = x.rLux();    


}

同样在摩托车

Motorcycle& Motorcycle::operator=( Motorcycle x)
{
    this->setModel(x.rModel()); 
    this->setMake(x.rMake());   
    this->setPrice(x.Vehicle::getPrice());
    this->setMileage(x.rMiles());
    this->setLot(x.rLot());
    this->setGas(x.rGas());
    this->style = x.rStyle();
    this->passenger = x.rPassenger();   

}

如果你帮助我，我会把你拉出来的一绺头发送给你。

完整代码：https://drive.google.com/folderview?id=0B7LaFMkHcgCAd3habUpjWUR0YU0&usp=sharing

Answer 1

在您的代码中，您可能错过了重新分配声明

car = new Car[size1];
for(int i = 0; i < count1; i++)
    car[i] = x.car[i];

之后你应该添加另一行让x再次指向汽车

x = car;

类似于电机！

希望这有帮助，但如果你想要动态数组，那么尝试使用向量（事实上它们很快：p）

C ++ Car Inventory，复制构造函数probs

1 个答案: