Oracle SQL获得每种帐户类型的最低余额

时间:2016-02-11 02:53:30

标签: sql oracle

我正在尝试列出客户的姓氏和名字,以及帐户类型/说明,但仅列出每种帐户类型余额最低的名称。 以下是我到目前为止的情况:

Select Surname || ', ' || First_name AS "Name", account_description
from WGB_CUSTOMER join WGB_ACCOUNT using (Customer_number) join              
WGB_ACCOUNT_TYPE using (Account_type)
where salary <ANY
(select MIN(Balance), account_type
 from wgb_account
Group by account_type);

这是一个错误,并且说的值太多了。代码的最后一部分(从选择MIN(余额)开始,仅显示仅具有最低余额的帐户类型。

如果有人能提供帮助,我将非常感激。对不起,英语不是我的第一语言。

感谢。

1 个答案:

答案 0 :(得分:0)

使用import System.IO import Control.Applicative import Data.Maybe data Value = Str String | Number Double | Boo Bool | Object [(String, Value)] | Array [Value] | Null deriving (Eq, Ord, Show) class Deserial a where deserialize :: Value -> Maybe a data Person = Person String Double deriving (Show) makePerson name age = case age of Number n -> Just (Person name n) _ -> Nothing instance Deserial Person where deserialize v = case v of Object [(name, age)] -> makePerson name age _ -> Nothing getString (Str s) = s getNumber (Number n) = Just n getNumber _ = Nothing main = do let jason = Object[("TestName", Number 3)] let _deserialized = _deserialize jason --this next line does not compile let deserialized = deserialize jason

rank() over (partition by

使用Select Name, account_description from ( select Surname || ', ' || First_name AS Name account_description rank() over (partition by Account_type order by Balance) rnk from WGB_CUSTOMER ) x where rnk = 1;

join