Question

我喜欢这样：

$data = array(
    "City_0" => "London",
    "City_1" => "Paris",
    "City_2" => "Lisbon",
    "City_3" => "Berlin"
    );

加上同一个数组中的其他一些数据。

用户只会选择其中一个，我需要的是：

使用preg_match检查以获取以“city _”
找到具有值的键（它不为空），取该值
将其分配给新密钥
删除所有“city_”键
将新密钥添加到名为“chosen_city”的数组中，该名称将包含该值

我尝试了什么：

foreach ($data as $key => $value) {
    $matches = preg_match('/city_/i', $key);

    if ($value != "") {
        $newValue = $value;

        break;
    }
}

$data['chosen_city'] = $newValue;


print_r($data);

这部分有效，如何在if语句中从数组中删除所有以前的“city_”键？

注意：我在数组中有其他键，我也不想删除它们。

输入数组：

$data = array(
        "City_0" => "London",
        "City_1" => "Paris",
        "City_2" => "Lisbon",
        "City_3" => "Berlin",
        "distance" => "5 km",
        "days" =>   "7",
        "tickets" => "2",
        "discount" => "10%",
        );

预期产出：

$data = array(
            "chosen_city" => "Berlin",
            "distance" => "5 km",
            "days" =>   "7",
            "tickets" => "2",
            "discount" => "10%",
            );

感谢。

Answer 1

请输入未设置的示例代码：

$data = array( "City_0" => "London", "City_1" => "Paris", "City_2" => "Lisbon", "City_3" => "Berlin");
foreach($data as $key => $value){
    $matches = preg_match('/city_/i', $key);

    if($matches && $value != ""){
        $newValue = $value;
        unset($data[$key]);
    }elseif($matches){
        unset($data[$key]);
    }

}

$data['chosen_city'] = $newValue;

Answer 2

在这种情况下，

preg_ *有点矫枉过正 - 你可以使用strpos并且它也可以正常工作

然而，问题是如何删除city_ *键＆＃39;，为此，只需使用unset（）：

foreach($data as $key => $value){
    $matches = preg_match('/city_/i', $key);

    if($value != ""){
        $newValue = $value;
        unset($data[$key]); //Remove this item from the array
        break;
    }
}

$data['chosen_city'] = $newValue;


print_r($data);

Answer 3

$data = array(
    "City_0" => "London",
    "City_1" => "Paris",
    "City_2" => "Lisbon",
    "City_3" => "Berlin",
    "distance" => "5 km",
    "days" =>   "7",
    "tickets" => "2",
    "discount" => "10%",
);

$value = 'Berlin';
if (array_search($value, $data)) {
    $data['chosen_city'] = $value;
    foreach ($data as $key=>$val) {
        if (stripos($key, 'city_')===0) {
            unset($data[$key]);
        }
    }
}

结果：

array(5) {
  'distance' =>
  string(4) "5 km"
  'days' =>
  string(1) "7"
  'tickets' =>
  string(1) "2"
  'discount' =>
  string(3) "10%"
  'chosen_city' =>
  string(6) "Berlin"
}

如果你使用PHP＆gt; = 5.6，可能你可以使用（我没有测试过这段代码）

$city = array_search($value, $data);
if ($city) {
    $data['chosen_city'] = $value;
    $data = array_filter($data,function($key,$val){return stripos($key,'city_')===false;},ARRAY_FILTER_USE_BOTH);
}

Preg匹配数组键

3 个答案: