Question

我试图在不使用REVERSE函数的情况下反转字符串。我遇到了一个例子：

select listagg(letter) within group(order by lvl)
from 
 (SELECT LEVEL lvl, SUBSTR ('hello', LEVEL*-1, 1) letter 
 FROM   dual 
 CONNECT BY LEVEL <= length('hello'));

除了这种方法，还有其他更好的方法吗？

Answer 1

如果您试图避免使用未记录的reverse()功能，则可以使用utl_raw.reverse() function代替，也可以使用RAW进行适当的转换：

select utl_i18n.raw_to_char(
  utl_raw.reverse(
    utl_i18n.string_to_raw('Some string', 'AL32UTF8')), 'AL32UTF8')
from dual;

UTL_I18N.RAW_TO_CHAR(UTL_RAW.REVERSE(UTL_I18N.STRING_TO_RAW('SOMESTRING','AL32UT
--------------------------------------------------------------------------------
gnirts emoS

所以这是一个原始的价值;对此进行utl_i18n.string_to_raw();然后将其传递给utl_raw.reverse();然后将结果传递回utl_i18n.raw_to_char()。

不完全确定这将如何应对多字节字符，或者您想要发生在那些人身上......

或来自the discussion @RahulTripathi linked to的变体，没有字符集处理：

select utl_raw.cast_to_varchar2(utl_raw.reverse(utl_raw.cast_to_raw('Some string')))
from dual;

UTL_RAW.CAST_TO_VARCHAR2(UTL_RAW.REVERSE(UTL_RAW.CAST_TO_RAW('SOMESTRING')))   
--------------------------------------------------------------------------------
gnirts emoS

但该线程还指出它只适用于单字节字符。

Answer 2

你可以这样做：

with strings as (select 'hello' str from dual union all
                 select 'fred' str from dual union all
                 select 'this is a sentance.' from dual)
select str,
       replace(sys_connect_by_path(substr (str, level*-1, 1), '~|'), '~|') rev_str 
from   strings
where  connect_by_isleaf = 1
connect by prior str = str                  --added because of running against several strings at once
           and prior sys_guid() is not null --added because of running against several strings at once 
           and level <= length(str);

STR                 REV_STR             
------------------- --------------------
fred                derf                
hello               olleh               
this is a sentance. .ecnatnes a si siht

N.B。我使用了~|的分隔符，因为这不太可能是你字符串的一部分。你需要为sys_connect_by_path提供一个非空的分隔符，因此我不能把它留空！

Answer 3

您可以尝试使用此功能：

SQL> ed
Wrote file afiedt.buf

  1  with t as (select 'Reverse' as txt from dual)
  2  select replace(sys_connect_by_path(ch,'|'),'|') as reversed_string
  3  from (
  4        select length(txt)-rownum as rn, substr(txt,rownum,1) ch
  5        from t
  6        connect by rownum <= length(txt)
  7       )
  8  where connect_by_isleaf = 1
  9  connect by rn = prior rn + 1
 10* start with rn = 0
SQL> /

Source

Answer 4

SELECT LISTAGG(STR) WITHIN GROUP (ORDER BY RN DESC)
FROM 
(
     SELECT ROWNUM RN, SUBSTR('ORACLE',ROWNUM,1) STR FROM DUAL 
     CONNECT BY LEVEL <= LENGTH('ORACLE')
);

如何在不使用REVERSE（）函数的情况下反转Oracle（11g）SQL中的字符串

4 个答案: