Question

我试图对已删除网站的每个元素进行分组，将其转换为json元素，但它似乎无法正常工作。

<?php

// Include the php dom parser    
include_once 'simple_html_dom.php';

header('Content-type: application/json');

// Create DOM from URL or file

$html = file_get_html('urlhere');

foreach($html->find('hr ul') as $ul)
{
    foreach($ul->find('div.product') as $li) 
    $data[$count]['products'][]['li']= $li->innertext;
    $count++;
}
echo json_encode($data);

?>

返回

{"":{"products":[{"li":"   <a class=\"th\" href=\"\/products\/56942-haters-crewneck-sweatshirt\">            <div style=\"background-image:url('http:\/\/s0.merchdirect.com\/images\/15814\/v600_B_AltApparel_Crew.png');\">         <img src=\"http:\/\/s0.com\/images\/6398\/product-image-placeholder-600.png\">       <\/div>                  <\/a>   <div class=\"panel panel-info\" style=\"display: none;\">     <div class=\"name\">       <a href=\"\/products\/56942-haters-crewneck-sweatshirt\">                    Haters Crewneck Sweatshirt                <\/a>     <\/div>     <div class=\"subtitle\">                                                                                                                                                                                                                                                                                                                                  $60.00                                 <\/div>   <\/div> "}

当我真的希望实现时：

{"products":[{
"link":"/products/56942-haters-crewneck-sweatshirt",
"image":"http://s0.com/images/15814/v600_B_AltApparel_Crew.png",
"name":"Haters Crewneck Sweatshirt",
 "subtitle":"60.00"}
]}

如何摆脱所有冗余信息，并可能在重新格式化的json中命名每个元素？

谢谢！

Answer 1

您只需要在内循环中扩展逻辑：

foreach($html->find('hr ul') as $ul)
{
    foreach($ul->find('div.product') as $li) {
        $product = array();

        $product['link'] = $li->find('a.th')[0]->href;
        $product['name'] = trim($li->find('div.name a')[0]->innertext);
        $product['subtitle'] = trim($li->find('div.subtitle')[0]->innertext);
        $product['image'] = explode("'", $li->find('div')[0]->style)[1];

        $data[$count]['products'][] = $product;
    }

}
echo json_encode($data);

使用简单的HTML DOM解析器到JSON？

1 个答案: