Question

我正在使用C＃/。NET library 来实施Asterisk RESTful Interface (ARI)来创建电话会议应用。

到目前为止，应用程序的工作原理如下：

用户拨打号码
App答案
App开始语音检测
App请求姓名并录制音频
App将用户添加到会议中

要求：

在将用户添加到会议之前，我需要在上述过程中添加某种授权。我需要实施询问PIN码功能，创建PIN号码构造，如果来电者输入正确的PIN码，则将来电者添加到正确的电话会议中。

守则：

会议

    public Conference( AriClient c, Guid id, string name)
    {
        _client = c;
        Id = id;
        ConferenceName = name;
        State = ConferenceState.Destroyed;

        c.OnChannelDtmfReceivedEvent += c_OnChannelDtmfReceivedEvent; // ??
        c.OnBridgeCreatedEvent += c_OnBridgeCreatedEvent;
        c.OnChannelEnteredBridgeEvent += c_OnChannelEnteredBridgeEvent;
        c.OnBridgeDestroyedEvent += c_OnBridgeDestroyedEvent;
        c.OnChannelLeftBridgeEvent += c_OnChannelLeftBridgeEvent;
        c.OnRecordingFinishedEvent += c_OnRecordingFinishedEvent;

        // Added support for talk detection
        c.OnChannelTalkingStartedEvent += c_OnChannelTalkingStartedEvent;
        c.OnChannelTalkingFinishedEvent += c_OnChannelTalkingFinishedEvent;

        Debug.Print("Added Conference {0}", ConferenceName);
    }

OnChannelEnteredBridgeEvent：

private void c_OnChannelEnteredBridgeEvent(object sender, ChannelEnteredBridgeEvent e)
{
    ConferenceUser confUser = ConferenceUsers.SingleOrDefault(x => x.Channel.Id == e.Channel.Id);
    if (confUser == null) return;

    confUser.State = ConferenceUserState.InConf;

    if (ConferenceUsers.Count(x => x.State == ConferenceUserState.InConf) > 1) // are we the only ones here
    {
        // stop moh
        _client.Bridges.StopMoh(Confbridge.Id);

        // change state
        State = ConferenceState.Ready;

        // announce new user
        _client.Bridges.Play(Confbridge.Id, "recording:" + confUser.CurrentRecodingId, "en", 0, 0, Guid.NewGuid().ToString());
        _client.Bridges.Play(Confbridge.Id, "sound:conf-hasjoin", "en", 0, 0, Guid.NewGuid().ToString());
    }
    else
    {          
        // only caller in conf
        _client.Channels.Play(e.Channel.Id, "sound:conf-onlyperson", "en", 0, 0, Guid.NewGuid().ToString());
    }
}

StartConference：

    public bool StartConference()
    {

        // Create the conference bridge
        Debug.Print("Requesting new bridge {0} for {1}", Id, ConferenceName);
        Bridge bridge = _client.Bridges.Create("mixing", Id.ToString(), ConferenceName);

        if (bridge == null)
        {
            return false;
        }

        Debug.Print("Subscribing to events on bridge {0} for {1}", Id, ConferenceName);
        _client.Applications.Subscribe(AppConfig.AppName, "bridge:" + bridge.Id);

        // Start MOH on conf bridge
        _client.Bridges.StartMoh(bridge.Id, "default");

        // Default state is ReadyWaiting until MOH is turned off
        State = ConferenceState.ReadyWaiting;
        Confbridge = bridge;

        // Conference ready to accept calls
        State = ConferenceState.Ready;

        return true;
    }

ADDUSER：

    public bool AddUser(Channel c) //here check for pin and caller id
    {
        if (State == ConferenceState.Destroying)
            return false;
        if (State == ConferenceState.Destroyed)
        {
            // We should initiate a new conference bridge
            if (!StartConference())
                return false;
        }
        if (State < ConferenceState.Ready) return false;

        // Answer channel
        _client.Channels.Answer(c.Id);

        // Turn on talk detection on this channel
        _client.Channels.SetChannelVar(c.Id, "TALK_DETECT(set)", "");

        // Add conference user to collection
        ConferenceUsers.Add(new ConferenceUser(this, c, _client, ConferenceUserType.Normal));

        return true;
    }

问题：

如何提出/调用＆＃34;询问引脚号＆＃34;应用程序中的事件/频道并将输入的DTMF数字抓取到变量中？

这可以仅在我的C＃ARI应用程序中完成，还是我需要在Asterisk服务器上摆弄.conf文件？

我首选的方法是在我的C＃ARI应用程序中实现它，因为这可以让我更好地控制会议。

Answer 1

你应该创建一些拨号方案来支持它，并要求拨号方案检查你的插针等

当然可以在没有拨号方案支持的情况下完成，但在这种情况下，任务成为大师级别，没有真正意义上的那样。

首先，我可以向您推荐“Asterisk the telephony”一书。

您可以使用func_odbc，读取应用程序，CHANNEL函数（用于ip）

Asterisk ARI电话会议应用：授权/询问密码

1 个答案: