在org.apache.xmlrpc.webserver中，ConnectionServer不公开;无法从外部包

Question

在两个不同的地方，Apache XML-RPC的文档建议实例化org.apache.xmlrpc.webserver.ConnectionServer对象：Custom Data Types和Introspection

然而，当我尝试这样做时：

import java.net.InetAddress;
import java.io.IOException;
import org.apache.xmlrpc.server.PropertyHandlerMapping;
import org.apache.xmlrpc.server.XmlRpcServer;
import org.apache.xmlrpc.server.XmlRpcServerConfigImpl;
import org.apache.xmlrpc.webserver.WebServer;
import org.apache.xmlrpc.webserver.ConnectionServer;
import org.apache.xmlrpc.XmlRpcException;

public class XMLRPCServer extends WebServer {
    public XMLRPCServer(int port) throws XmlRpcException, IOException {
        super(port);

        XmlRpcServer xmlRpcServer = getXmlRpcServer();

        PropertyHandlerMapping phm = new PropertyHandlerMapping();
        phm.addHandler("MyHandler", MyXMLRPCService.class);
        xmlRpcServer.setHandlerMapping(phm);
        XmlRpcServerConfigImpl serverConfig = (XmlRpcServerConfigImpl) xmlRpcServer.getConfig();
    }

    protected XmlRpcStreamServer newXmlRpcStreamServer() {
        XmlRpcStreamServer server = new ConnectionServer();
        return server;
    }
}

我收到此错误：

[javac] <path>/communication/xmlrpc/XMLRPCServer.java:8: error: ConnectionServer is not public in org.apache.xmlrpc.webserver; cannot be accessed from outside package
[javac] import org.apache.xmlrpc.webserver.ConnectionServer;
[javac]                                   ^

我做错了什么吗？或者它是doc / library中的错误？

Answer 1

我找到了解决方法：

    protected XmlRpcStreamServer newXmlRpcStreamServer() {
        XmlRpcStreamServer server = super.newXmlRpcStreamServer();
        return server;
    }