Question

使用VTD-XML 2.11（Java）API，在Simple文本或xml元素上评估XPath表达式 concat（），而不是得到2.0的结果时，它会失败并出现以下异常：

Exception in thread "main" com.ximpleware.XPathEvalException:  Function Expr can't eval to node set 
    at com.ximpleware.FuncExpr.evalNodeSet(FuncExpr.java:1033)
    at com.ximpleware.AutoPilot.evalXPath(AutoPilot.java:876)

以下是以下计划：

private static String getElementValue() throws XPathParseException, XPathEvalException, NavException {
    String value = null;

    VTDGen gen = new VTDGen();
    gen.setDoc(data.getBytes());
    gen.parse(false);

    VTDNav nav = gen.getNav();

    AutoPilot pilot = new AutoPilot(nav);
    pilot.selectXPath("concat(\"Hello\", \"Mr Buddy\")");

    int bufferIndex = NO_MATCH;
    if((bufferIndex = pilot.evalXPath()) != NO_MATCH) {
        value= nav.getXPathStringVal();
    }
    System.out.println(value);
} // end of getElementValue()

Answer 1

这是我的代码，它似乎对我很好......看看它，让我知道你的想法..

import com.ximpleware.*;
public class concatTest{
    public static void main(String s1[]) throws Exception {
        VTDGen vg= new VTDGen();
        String s = "<users><user><firstName>some </firstName><lastName> one</lastName></user></users>";
        vg.setDoc(s.getBytes());
        vg.parse(false);
        VTDNav vn = vg.getNav();
        AutoPilot ap = new AutoPilot();
        ap.selectXPath("concat('good', ' luck')");
        System.out.println(" concat output ==>"+ap.evalXPathToString());
        ap.selectXPath("concat(/, '')");
        ap.bind(vn);
        System.out.println(" concat output ==>"+ap.evalXPathToString());
    }

}

concat（）函数在VTD-XML中使用AutoPilot时，XPath评估失败

1 个答案: