我的数据库上的每门课程都有一个相应的faculty_id。
每个教师都与其他院系有亲密关系(因此,教师队伍的课程也是如此)。教师的亲密关系和课程亲和力是与表格相关的。
我正在尝试构建一个触发器,当删除faculty_affinity上的记录时,该触发器会删除course_affinity表中的记录。
这就是我所拥有的。它不起作用。
CREATE TRIGGER deleteCourses
AFTER DELETE
ON faculty_affinities
AS
BEGIN
DELETE FROM course_affinities
JOIN courses AS course1
JOIN courses AS course2
ON course_affinities.course1_id = course1.id
AND course_affinities.course2_id = course2.id
WHERE (course1.faculty_id = DELETED.faculty1_id OR course1.faculty_id = DELETED.faculty2_id)
AND (course2.faculty_id = DELETED.faculty1_id OR course2.faculty_id = DELETED.faculty2_id);
END;
帮助别人?我做错了什么?
编辑:我收到错误
SQLSTATE[4200]: Syntax error... neas 'AS at line 4
Edit2:我的迁移
Schema::create('courses', function (Blueprint $table) {
$table->increments('id');
$table->string('name', 150);
$table->integer('faculty_id')->unsigned();
$table->foreign('faculty_id')->references('id')->on('faculties');
$table->boolean('active')->default(1);
//$table->softDeletes();
});
Schema::create('faculties', function (Blueprint $table) {
$table->increments('id');
$table->string('name', 150)->unique();
$table->boolean('active')->default(1);
//$table->softDeletes();
});
Schema::create('course_affinities', function (Blueprint $table) {
$table->increments('id');
$table->integer('course1_id')->unsigned();
$table->foreign('course1_id')->references('id')->on('courses');
$table->integer('course2_id')->unsigned();
$table->foreign('course2_id')->references('id')->on('courses');
$table->boolean('active')->default(1);
//$table->softDeletes();
});
Schema::create('faculty_affinities', function (Blueprint $table) {
$table->increments('id');
$table->integer('faculty1_id')->unsigned();
$table->foreign('faculty1_id')->references('id')->on('faculties');
$table->integer('faculty2_id')->unsigned();
$table->foreign('faculty2_id')->references('id')->on('faculties');
$table->boolean('active')->default(1);
//$table->softDeletes();
});
答案 0 :(得分:1)
您的代码看起来可能是为MS SQL Server而不是MySQL编写的(使用deleted
虚拟表提示);相应的MySQL语法应如下所示:
CREATE TRIGGER deleteCourses
AFTER DELETE ON faculty_affinities
FOR EACH ROW
BEGIN
DELETE ca
FROM course_affinities ca
JOIN courses AS course1 ON ca.course1_id = course1.id
JOIN courses AS course2 ON ca.course2_id = course2.id
WHERE (course1.faculty_id = OLD.faculty1_id OR course1.faculty_id = OLD.faculty2_id)
AND (course2.faculty_id = OLD.faculty1_id OR course2.faculty_id = OLD.faculty2_id);
END;
我还没有对它进行过测试,所以请继续关注......