如何确定WHERE子句的哪一部分导致无法找到行？

Question

我知道如果满足SQL String语句，next（）将继续检查每一行。否则，如果它不能满足SQL Select语句，则为false。 （我希望我没有错过任何东西）

如果我的陈述是

ResultSet myRs1 = null;
            String SQL1 = "SELECT * FROM USERS WHERE USERNAME = ? AND PASSWORD = ? AND USERTYPE = ?";

如果textfield上的用户名值与行中的用户名匹配但是密码在同一列中不匹配，我应该使用哪种方法？ 此外，如果rowCounter返回false并将false计为0，我该如何比较密码？我想到了吸气剂

我想做点什么

if((usernameInTextField found in current row) BUT (passwordInTextField doesn't match password in current row))
Print message "Password Incorrect"

请耐心等待我，因为我是JDBC的新手。

这是我的代码：

ResultSet myRs1 = null;
            String SQL1 = "SELECT * FROM USERS WHERE USERNAME = ? AND PASSWORD = ? AND USERTYPE = ?";


        try {
          myConnection = DriverManager.getConnection(dbURL,username,password);
            JOptionPane.showMessageDialog(null, "Successfully Connected To Database");

            PreparedStatement myPrepStmt = myConnection.prepareStatement(SQL1);
                myPrepStmt.setString(1,userNameEntered); //assigns a string value to the first ?
                myPrepStmt.setString(2,passwordEntered); //assigns a string value to the second ?
                myPrepStmt.setString(3,userTypeEntered);
            myRs1 = myPrepStmt.executeQuery(); // executes the select query and stores it to myRs

            int rowCounter = 0;
            while(myRs1.next()) //as long as query is satisfied, next() will return true
            {
                rowCounter++; 
            }

            if(rowCounter == 0) 
            {
                JOptionPane.showMessageDialog(this, "Username, Password or Usertype maybe incorrect");
            }
            else if(rowCounter > 1) //if there are duplications 
            {
                JOptionPane.showMessageDialog(null, "User details found but has more 1 one entry" +
                        "\nFound: " + rowCounter + " rows" );
            }
            else if(rowCounter == 1){
                JOptionPane.showMessageDialog(null, "Found " + rowCounter + " record");
            }


        } //end of try
        catch (SQLException e) {
}

我的代码使用rowCounter，但无法指定哪个不正确（用户名/密码/ usertype）。

感谢。